Home>Article>PHP Framework> How to implement collection function and switch colors in tp5
html page, references the bootstrap icon
{if condition="$color == 5"}{else/}
{/if}
css style
js in
$("#collection").click(function(){ $.ajax({ type:'POST', url:"home_collection.html", data:{ "art_id": {$data['id']}, // 传过去文章表的id }, dataType:"json", success:function(data){ var res = JSON.parse(data); // json 字符串转化为对象 if (res.code == '3') // 收藏成功,变成红色 { $('#collection').toggleClass('cs'); // document.getElementById('collection').style.background="#FF0000"; // 另一种样式,这是把整个背景都变红了 console.log(res.code); } if (res.code == '4') // 取消收藏 { $('#collection').toggleClass('cs'); console.log(res.code); } }, error:function(data){ console.log(data); console.log(data.code); alert(222); } }); });
controller
// 当图标变颜色的时候,点击是取消收藏,当图片没颜色的时候点击是收藏 // 查询数据库是否存在,如果不存在则加入,存在则删除,前台也变样式 public function collection() { $data = $_POST; $uname1 = session::get('USER_INFO'); $uid = $uname1['uid']; // 应该查询当前用户对应的art_id 存不存在在 收藏表 中 $result = DB::name('collection')->where('art_id',$data['art_id'])->select(); if($result) { $aa = DB::name('collection')->where('art_id',$data['art_id'])->delete(); $returnData = ['code'=>4, 'info'=>'取消收藏']; }else{ $bb['art_id'] = $data['art_id']; // 对应文章表的id $bb['uid'] = $uid ; $bb = DB::name('collection')->insert($bb); $returnData = ['code'=>3, 'info'=>'收藏成功']; } // header('Content-Type:application/json; charset=utf-8'); $data3 = json_encode($returnData,JSON_UNESCAPED_UNICODE); //这样也正确 return $data3; // return json_encode($returnData);// 这样返回格式正确 }
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