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Java uses lambda expression to sort a certain attribute of List object collection

王林
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2019-12-14 12:00:03 7653browse

Java uses lambda expression to sort a certain attribute of List object collection

Create a new UserInfo object here to test lambda expression sorting. The properties are as follows:

public class UserInfo { private int id; private int age; private String name; public UserInfo(int id, int age, String name) { this.id = id; this.age = age; this.name = name; } public int getId() { return id; } public void setId(int id) { this.id = id; } public int getAge() { return age; } public void setAge(int age) { this.age = age; } public String getName() { return name; }测试 public void setName(String name) { this.name = name; }

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Start creating data, and sort it in positive order by age during the test:

public static void main(String[] args) { UserInfo user1 = new UserInfo(1, 20, "赵"); UserInfo user2 = new UserInfo(2, 25, "钱"); UserInfo user3 = new UserInfo(3, 23, "孙"); UserInfo user4 = new UserInfo(7, 16, "李"); UserInfo user5 = new UserInfo(6, 19, "周"); UserInfo user6 = new UserInfo(5, 12, "吴"); List userInfoList = new ArrayList<>(); userInfoList.add(user2); userInfoList.add(user1); userInfoList.add(user3); userInfoList.add(user4); userInfoList.add(user5); userInfoList.add(user6); //使用lambda表达式对age大小正序排序 userInfoList = userInfoList.stream().sorted(Comparator.comparing(UserInfo::getAge)) .collect(Collectors.toList()); for (UserInfo userInfo : userInfoList) { System.out.println(userInfo.toString()); } }

The output results are as follows:

Java uses lambda expression to sort a certain attribute of List object collection

The test is sorted in reverse order by age. :

public static void main(String[] args) { UserInfo user1 = new UserInfo(1, 20, "赵"); UserInfo user2 = new UserInfo(2, 25, "钱"); UserInfo user3 = new UserInfo(3, 23, "孙"); UserInfo user4 = new UserInfo(7, 16, "李"); UserInfo user5 = new UserInfo(6, 19, "周"); UserInfo user6 = new UserInfo(5, 12, "吴"); List userInfoList = new ArrayList<>(); userInfoList.add(user2); userInfoList.add(user1); userInfoList.add(user3); userInfoList.add(user4); userInfoList.add(user5); userInfoList.add(user6); //使用lambda表达式对age大小倒序排序,发现就是多加了个reversed()方法 userInfoList = userInfoList.stream().sorted(Comparator.comparing(UserInfo::getAge). reversed()).collect(Collectors.toList()); for (UserInfo userInfo : userInfoList) { System.out.println(userInfo.toString()); } }

The output results are as follows:

Java uses lambda expression to sort a certain attribute of List object collection

Summarize the sorting method:

1. Sort according to a certain field in positive order:

userInfoList.stream().sorted(Comparator.comparing(UserInfo::getAge)).collect(Collectors.toList());

2. Sort in reverse order according to a certain field:

userInfoList.stream().sorted(Comparator.comparing(UserInfo::getAge).reversed()).collect(Collectors.toList());

Just adjust the above parameters according to your business.

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