Find a non-repeating number in the array. The question is roughly like this:
int[] a = { 1, 2, 3, 4, 3, 2, 1 };
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The solution is:
public static int getNoRepeat() { int[] a = { 1, 2, 3, 4, 3, 2, 1 }; for (int i = 0; i < a.length; i++) { int b = 0; for (int j = 0; j < a.length; j++) { if (a[i] == a[j]) { b++; } } if (b == 1) { return a[i]; } } return 0; }
The idea is to compare the first number in the array with each number in the array. If the same number is equal to 2, it is repeated, and if it is equal to 1, it is not Repeated.
If you want to find repeated numbers, just replace b==1 with b==2.
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