
Java method to determine whether it is a number: (Recommended: java video tutorial)
Method 1: Use JAVA’s own function
public static boolean isNumeric(String str){
for (int i = str.length();--i>=0;){
if (!Character.isDigit(str.charAt(i))){
return false;
}
}
return true;
}Method Two:
/*
* 判断是否为整数
* @param str 传入的字符串
* @return 是整数返回true,否则返回false
*/
public static boolean isInteger(String str) {
Pattern pattern = Pattern.compile("^[-\+]?[\d]*$");
return pattern.matcher(str).matches();
}Method Three:
public static boolean isNumeric(String str){
Pattern pattern = Pattern.compile("[0-9]*");
return pattern.matcher(str).matches();
}Method Four:
public final static boolean isNumeric(String s) {
if (s != null && !"".equals(s.trim()))
return s.matches("^[0-9]*$");
else
return false;
}Method Five: Use ascii code
public static boolean isNumeric(String str){
for(int i=str.length();--i>=0;){
int chr=str.charAt(i);
if(chr<48 || chr>57)
return false;
}
return true;
}For more java knowledge, please pay attention to the java basic tutorial column.
The above is the detailed content of Introduction to the method of judging whether it is a number in Java. For more information, please follow other related articles on the PHP Chinese website!