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How to accept post value in php

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(*-*)浩Original
2019-09-09 11:54:005208browse

During this time, I was studying the interface of PHP, using jmeter to simulate sending data to the PHP server, to see how PHP receives the data transmitted by POST. I encountered several problems. After some trouble, I finally understood it and recorded it. :

How to accept post value in php

Here are two commonly used post methods

The first one:

content-type is application/x-www-form-urlencoded, which is the default data format for post. When using jquery's ajax to post data, the default is this way. The data format transmitted in this way is: username =admin&password=123456. (Recommended learning: PHP programming from entry to proficiency)

The most commonly used $_POST method is used when the server receives it. To obtain the username, use $_POST['username']. Get it normally.

Second:

After studying this method for a long time, I found out how to receive and process the data. The content-type is application/json, in php It is impossible to directly receive the data format of application/json using $_POST method. The data type in application/json format is:

{
"username":"admin",
"password":"123455"
}

For this data type posted to the server, In PHP, the data type needs to be received natively through 'php://input' (the post transmitted data mode), and then use json_encode to parse, and then operate , the php code is:

$raw_post_data = file_get_contents('php://input');
$arr = json_decode($raw_post_data,true);
echo $arr['username'];

At this point, you can obtain application/x-www-form-urlencoded format data through $_POST[ 'username'] obtains the format of application/json data.

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