How to sort python dictionary by value

sorted function

First introduce the sorted function, sorted (iterable, key, reverse), sorted has three types: iterable, key, reverse parameters.

Iterable represents an object that can be iterated, such as dict.items(), dict.keys(), etc. key is a function used to select the elements participating in the comparison, and reverse is used to specify the sorting Is it in reverse order or order? reverse=true means reverse order (from large to small), reverse=false means order (from small to large), and the default is reverse=false.

Sort by value

There are three ways to sort the dictionary by value

key uses the lambda anonymous function to take the value and sort it

d = {'lilee':25, 'wangyan':21, 'liqun':32, 'age':19}
sorted(d.items(), key=lambda item:item[1])

The output result is

[('age',19),('wangyan',21),('lilee',25),('liqun',32)]

If you need to reverse the order, the result obtained by

sorted(d.items(), key=lambda item:item[1], reverse=True)

will be

[('liqun',32),('lilee',25),('wangyan',21),('age',19)]

using the operator itemgetter sorts

import operator
sorted(d.items(), key=operator.itemgetter(1))

The output result is

[('age',19),('wangyan',21),('lilee',25),('liqun',32)]

Divide the key and value into tuples, and then sort them

f = zip(d.keys(), d.values())
c = sorted(f)

The output result is

[('age',19),('wangyan',21),('lilee',25),('liqun',32)]

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