LeetCode Maximum Length of Repeated Subarray

This article introduces the Maximum Length of Repeated Subarray of LeetCode. I hope you will learn patiently.

Given two integer arraysAandB, return the length of the common and longest subarray in the two arrays.

Example 1:

输入:A: [1,2,3,2,1] B: [3,2,1,4,7]输出: 3解释: 长度最长的公共子数组是 [3, 2, 1]。

Instructions:

1. 1 <= len (A), len(B) <= 1000

2. ##0 <= A[i], B[i] < 10

public class MaxLengthRepeatedSubarray { //动态规划算法 public static int findLength(int[] A, int[] B) { int aSize = A.length; int bSize = B.length; int[][] dp = new int[aSize + 1][bSize + 1]; int result = 0; for (int i = 1; i < dp.length; i++) { for (int j = 1; j < dp[i].length; j++) { dp[i][j] = A[i - 1] == B[j - 1] ? dp[i - 1][j - 1] + 1 : 0; result = Math.max(result, dp[i][j]); } } return result; } public static void main(String[] args) { int[] a = new int[]{1, 2, 3, 2, 1}; int[] b = new int[]{3, 2, 1, 4, 7}; System.out.println(findLength(a, b)); } }

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