Detailed explanation of cases using generic methods in java

I tried to write a sorting generic method, but it turned out that I needed to use compareTo. But when the compiler was compiling, it was found that it could not be used.

Later, when I was flipping through the book, I discovered that needs to be written as in order to use the compareTo function!

For generic construction arrays, new cannot be used to construct it, but only

str=(T[])Array.newInstance(a.getClass().getComponentType(),a.length);进行构造

. For initialization of generic classes, use

sorts<String>sort1=new sorts<>(str);

for generics. type, if you want to use compareTo, you cannot use the int class, you have to use the Integer class

Integer[] number=new Integer[lo];

Take quick sort as an example, the source code is as follows!

import java.lang.reflect.Array;
import java.util.Arrays;
import java.util.Scanner;


class sorts
{
    T[] str;
    sorts(T[]a){
     str=(T[])Array.newInstance(a.getClass().getComponentType(),a.length);
    for(int i=0;i=0)lo++;
            if(losort2=new sorts<>(number);
        sort2.quick_sort(0,number.length);
//       Arrays.sort(number);
       for(int i=0;i
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About generic classes, generic methods, and generic interfaces in java
Generics in Java Type method
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