PHP sorts according to longitude and latitude and filters distance segments according to longitude and latitude

This article mainly introduces about php sorting according to longitude and latitude, and filtering distance segments according to longitude and latitude. It has a certain reference value. Now I share it with you. Friends in need can refer to it.

SQL 语句： select location.* from (select *,round(6378.138*2*asin(sqrt(pow(sin( (36.668530*pi()/180-px_lat*pi()/180)/2),2)+cos(36.668530*pi()/180)*cos(px_lat*pi()/180)* pow(sin( (117.020359*pi()/180-px_lon*pi()/180)/2),2)))*1000) as distance from bsx_training where (px_state = 1) and (type_id != '') and (((px_lat >= 27.683290277922) and (px_lat 008b0d02af5e880524b45e5a244da4e2= 105.81826766053) and (px_lon e67e6aa6f1d00bbfc85f18aa8b181075= {["minLat"]}) and (px_lat 71322fc885cb7c46ea769eb6fff02986= {['minLng']}) and (px_lon 4615b1a699ff3838c5fbc301a9257e34= {[0]}) and (location.distance 12b943c66ffff944f0d062a653df4b62") !== = (">", .= " and (location.distance >= {[1]})"

The following is to calculate the data control function within the longitude and latitude range

/** * * @param $latitude 纬度 * @param $longitude 经度 * @param $raidus 半径范围(单位：米) * @return multitype:number */ function getAround($latitude,$longitude,$raidus) { $PI = 3.14159265; $degree = (24901*1609)/360.0; $dpmLat = 1/$degree; $radiusLat = $dpmLat*$raidus; $minLat = $latitude - $radiusLat; $maxLat = $latitude + $radiusLat; $mpdLng = $degree*cos($latitude * ($PI/180)); $dpmLng = 1 / $mpdLng; $radiusLng = $dpmLng*$raidus; $minLng = $longitude - $radiusLng; $maxLng = $longitude + $radiusLng; return array (minLat=>$minLat, maxLat=>$maxLat, minLng=>$minLng, maxLng=>$maxLng); }

To implement sorting according to longitude and latitude

Just call distance_sql(lon1,lat1,lon2,lat2) directly to pass in the parameters and as an alias such as as distance, and then order by in the sql statement is sorted according to distance

If the filter distance segment is 1000 Meter-2000 meter data

Then nest the sql statement sql

select *.loation from (select *,round(6378.138*2*asin(sqrt(pow(sin( (36.668530*pi()/180-px_lat*pi()/180)/2),2)+cos(36.668530*pi()/180)*cos(px_lat*pi()/180)* pow(sin( (117.020359*pi()/180-px_lon*pi()/180)/2),2)))*1000) as distance) from table location where (location.distance >= 1000) and (location.distance <= 2000))

If you implement sorting sql based on the nearest location

select *,round(6378.138*2*asin(sqrt(pow(sin( (36.668530*pi()/180-px_lat*pi()/180)/2),2)+cos(36.668530*pi()/180)*cos(px_lat*pi()/180)* pow(sin( (117.020359*pi()/180-px_lon*pi()/180)/2),2)))*1000) as distance order by distance

public function training_list() { $wheres1 = "(px_state = 1)"; $wheres2 = " where (1=1)"; $orderBy = " px_id desc"; if(I("post.location")){ // 用户经纬度 $location = explode(",",I("post.location")); $userLon = $location[0]; $userLat = $location[1]; // 经纬度筛选 $location = getAround($userLat,$userLon,1000000); $wheres1.=" and (((px_lat >= {$location["minLat"]}) and (px_lat e0e3adc5b1d21874bd68194c923dd33d= {$location['minLng']}) and (px_lon 26073fa122ec5ad079810924d812a7cf= {$km[0]}) and (location.distance 24d4f35e0098b2dac5d018927d5071cc") !== false){ $km = explode(">",$kmStr); $wheres2 .= " and (location.distance >= {$km[1]})"; } } } $showNum = 10; if(I("post.page")){ $page = I("post.page"); }else{ $page = 1; } $n = ($page-1)*$showNum; $field = "*{$distanceSql}"; $sql = "select location.* from (select {$field} from bsx_training where {$wheres1} order by {$orderBy} limit {$n},{$showNum}) location {$wheres2}"; $training = M()->query($sql); dump(M()->getlastsql());die; }

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