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HomeWeb Front-endJS TutorialJS implements the simplest search, sorting, and deduplication algorithm

This time I will bring you the simplest search, sorting, and deduplication algorithm implemented in JS. What are the things to pay attention to in JS implementation of search, sorting, and deduplication? The following is a practical case. Let’s take a look. one time. Today I summarized a simple sorting algorithm

[Custom sorting]

First find the smallest number, and then compare this number with other numbers in the array. If you find a number smaller than this number, swap the two numbers, and then continue to find the next smallest number for the next round of comparison

var arr = [31, 6, 19, 8, 2, 3];
function findMin(start, arr) {
  var iMin = arr[start];
  var iMinIndex = start;
  for (var i = start + 1; i <p style="text-align: left;">[Linear Search]: Search one by one</p> <pre class="brush:php;toolbar:false">//不重复 有序
var arr = [0];
for (var i = 1; i <p style="text-align: left;">【</p>Binary search<p style="text-align: left;">】: Keep dividing it into two parts. Partial search<a href="//m.sbmmt.com/code/12110.html" target="_blank"></a> is a universal method, not necessarily the best, but a guaranteed method. . (Divide and conquer method)</p><p style="text-align: left;">***Add the middle values ​​and divide by two, uniformly left, round down</p><pre class="brush:php;toolbar:false">//不重复 有序
var arr = [12, 17, 23, 34, 45, 76, 89];
function find2(n, s, e) {
  //边界处理
  if (s > e) {
    return false;
  } else if (s == e) {
    if (arr[s] == n) {
      return true;
    } else {
      return false;
    }
  }
  var c = Math.floor((s + e) / 2);
  if (arr[c] == n) {
    return true;
  } else {
    if (n <p style="text-align: left;">[Boundary processing]-----Recursion, one level Find one layer down</p><pre class="brush:php;toolbar:false">//要求数组不重复有顺序\
var arr = [12, 23, 34, 45, 56, 67, 78]
function find2(n, s, e) {
  if (s > e) {
    return fasle;
  } else if (s == e) {
    if (arr[s] == e) {
      return true;
    } else {
      return false;
    }
  }
  var c = Math.floor((s + e) / 2);
  if (arr[c] == n) {
    return true;
  } else {
    if (n <p style="text-align: left;">Application</p><p style="text-align: left;">【Find minimum value】</p><pre class="brush:php;toolbar:false">var arr = [12, 54, 32, 9, 5, 3, 1, 101, -100, -1000];
function findMin(s, e) {
  if (s > e) {
    return [];
  } else if (s == e) {
    return arr[s];
  } else if (s == e - 1) {
    if (arr[s] <p style="text-align: left;">【Array deduplication】</p><pre class="brush:php;toolbar:false">var arr = [1, 2, 3, 4, 5, 4, 3, 4, 5, 2, 1, 4, 2, 1, 5, 7];
function findInArr(n, arr) {
  for (var i = 0; i  e) {
    return [];
  } else if (s == e) {
    return [arr[s]];
  } else if (s == e - 1) {
    if (arr[s] == arr[e]) {
      return [arr[s]];
    } else {
      return [arr[s], arr[e]]
    }
  }
  var c = Math.floor((s + e) / 2);
  var l = removeCopy(s, c);
  var r = removeCopy(c + 1, e);
  for (var i = 0; i <p style="text-align: left;">【</p>Array sorting<p style="text-align: left;">】<a href="//m.sbmmt.com/code/54.html" target="_blank"><pre class="brush:php;toolbar:false">var arr = [34, 32, 1, 76, 55, -100, 99, 101];
function mySort(s, e) {
  //边界处理
  if (s > e) {
    return [];
  } else if (s == e) {
    return [arr[s]]
  } else if (s == e - 1) {
    if (arr[s]  0 || r.length > 0) {
    if (l[0] 

Bubble sort

BubbleSortLoop, take out two values ​​​​each time and compare them two by two. If the next value is smaller than the current one, then Swap positions

The outer loop is to loop to get the numbers, and the inner loop is to swap the numbers in pairs

var arr = [ - 122, -2, 5, 6, 73, 34, 5, 2];
function BubbleSort(arr) {
  for (var i = 0; i  arr[j + 1]) {
        var tmp = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = tmp
      }
    }
  }
  return arr;
}
document.write(BubbleSort(arr));

[Quick Sort] -------quickSort

Get For the number in the middle of the array, place the number smaller than the middle number on the left side of the middle number, and the larger number than the middle number on the right side, and then link the two times together

function quickSort(arr, s, e) {
  //边界处理 参与流程
  if (arr.length == 0) {
    return [];
  }
  var c = Math.floor((s + e) / 2);
  var arrC = arr.splice(c, 1);
  var l = [];
  var r = [];
  for (var i = 0; i <p style="text-align: left;">[Hash] hash Hash array ------ Commonly used structures in js</p><p style="text-align: left;">Add</p><pre class="brush:php;toolbar:false">var arr = [];
arr.length = 0;
var cont = 0;
function hash_add(n) {
  var pos = n % arr.length;
  //当空间不足的时候
  if (arr[pos]) {
    while (arr[pos]) {
      cont++;
      if (arr[pos] == n) {
        return;
      } else {
        pos++;
        if (pos == arr.length) {
          pos = 0;
        }
      }
    }
    arr[pos] = n;
  } else {
    arr[pos] = n;
  }
  //空间不足的时候的扩建
  if (cont == arr.length) {
    //d等呗扩建
    var oldArr = arr;
    arr.length = oldArr.length * 2;
    arr = [];
    for (var i = 0; i <p style="text-align: left;"> I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the PHP Chinese website! </p><p>Recommended reading:</p><p></p>How to use the Vue-based lazy loading plug-in vue-view-lazy<p><a href="//m.sbmmt.com/js-tutorial-398758.html" target="_blank"></a><br>##How to use jquery toggleClass () attribute to create article paragraphs and change the background color</p><p><a href="//m.sbmmt.com/js-tutorial-398755.html" target="_blank"></a></p>

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