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How to implement file upload function in PHP

墨辰丷
墨辰丷Original
2018-05-22 14:57:481570browse

This article mainly introduces the example code of PHP to implement the file upload function. The code is simple and easy to understand, very good, and has reference value. Friends in need can refer to the following

Click to browse and select the selected file Upload to the created images folder

The code is as follows:

1.wenjian.php

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>无标题文档</title>
</head>
<body>
<h1>上传文件</h1>
<form action="chuli.php" method="post" enctype="multipart/form-data">
请选择文件:<input type="file" name="file" /><input type="submit" value="上传" />
</form>
</body>
</html>

2.chuli.php

<?php
//取文件信息
$arr = $_FILES["file"];
//var_dump($arr);
//加限制条件
//1.文件类型
//2.文件大小
//3.保存的文件名不重复
if(($arr["type"]=="image/jpeg" || $arr["type"]=="image/png" ) && $arr["size"]<10241000 )
{
//临时文件的路径
$arr["tmp_name"];
//上传的文件存放的位置
//避免文件重复: 
//1.加时间戳.time()加用户名.$uid或者加.date(&#39;YmdHis&#39;)
//2.类似网盘,使用文件夹来防止重复
$filename = "./images/".date(&#39;YmdHis&#39;).$arr["name"];
//保存之前判断该文件是否存在
  if(file_exists($filename))
  {
    echo "该文件已存在";
  }
  else
  {
  //中文名的文件出现问题,所以需要转换编码格式
  $filename = iconv("UTF-8","gb2312",$filename);
  //移动临时文件到上传的文件存放的位置(核心代码)
  //括号里:1.临时文件的路径, 2.存放的路径
  move_uploaded_file($arr["tmp_name"],$filename);
  }
}
else
{
  echo "上传的文件大小或类型不符";
}

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