Detailed explanation of the algorithm steps to implement statistics on the number of 1's in binary in PHP

This time I will bring you a detailed explanation of the algorithm steps to implement statistical counting of the number of 1's in a binary system in PHP. What are theprecautions. The following is a practical case. One Get up and take a look.

Question

Input a decimalinteger, and output the number of 1’s in the binary representation of the number. Negative numbers are expressed in two's complement.

Solution ideas

This is abit operationquestion.
Solution 1: You can find the number of 1's by ANDing each bit with 1 through bitwise AND operation.
Solution 2 (optimal solution): A clever method. A binary number that is not 0 must have at least one bit that is 1. When this number is reduced by one, its last bit of 1 will become 0. All subsequent 0's will be changed to 1's. For example, 10100 will become 10011 after subtracting one. Then, after ANDing the original numbers 10100 and 10011, you will get 10000. That is, through this operation, you can change a 1 into a 0, so how many times can a binary number be like this? There are as many operations as there are 1.

Implementation code

//解法一 function NumberOf1($n) { $count = 0; $flag = 1; while ($flag != 0) { if (($n & $flag) != 0) { $count++; } $flag = $flag << 1; } return $count; }

// 解法二 function NumberOf1($n) { $count = 0; if($n < 0){ // 处理负数 $n = $n&0x7FFFFFFF; ++$count; } while($n != 0){ $count++; $n = $n & ($n-1); } return $count; }

//测试 $num=45; echo $num."的二进制是".decbin($num)."
"; echo $num."共有".NumberOf1($num)."个1";

Running result:

I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!

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