How to get php parameters with special symbols such as # in the URL

This article mainly introduces to you the solution for PHP to obtain parameters with # and other special symbols in the URL. This article uses the escape function in JS to encode and pass to solve this problem. Friends who need it can refer to it. I hope it can help everyone. .

Today I encountered a front-end using vle.js with a # path. It needs to be transferred to the backend interface to obtain parameters, and then the interface url returns the current page.
The url that the front end will return is escaped today. Function escape
keys = escape(keys); //Encode the string, except * @ - _ + . / these characters
Processing on the php side, use the php get url function to first get the current url path, Convert it back through the rawurldecode function
$aurl = rawurldecode($aurl);
$url = explode('url=',$aurl)[1];
This way you can use the # sign in the url Jumped

Busy first is an example of function usage:

For example, the following PHP code:

<?php
echo $_GET[&#39;key&#39;];
?>

When the url is http://test.com/ When c.php?key=999, the normal output is: 999
When the url is http://test.com/c.php?key=9#888, it can only output: 9
and I want I got 9#888, what should I do? We can only find a way to pass 9#888 to the key.
I solved this problem by encoding and passing the escape function in JS. Friends in need can refer to it.

<input placeholder="输入SN码" type="text" id="searchs" name="searchs" />
<a class=&#39;btn&#39; onclick="searchsn();" href="javascript:;">查询</a>
<script>
    function searchsn() {
        var keys = $(&#39;#searchs&#39;).val();
        if (keys == &#39;&#39;) {
            alert(&#39;请填写SN码&#39;);
            return false;
        }
        keys = escape(keys); //对字符串进行编码，* @ - _ + . / 这几个字符除外
        window.location.href = &#39;c.php?key=&#39; + keys;
    }

</script>

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