Detailed explanation of the use of (urlparse) templates in python

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1. Introduction

urlparse module users parse the url into 6 components and use tuples Return in the form, the six parts returned are: scheme (protocol), netloc (network location), path (path), params (path segment parameters), query (query), fragment (fragment).

2. Function enumeration

1. urlparse.urlparse()(Parse url into components, url must be Starting with http://)

>>> urlparse.urlparse("https://i.cnblogs.com/EditPosts.aspx?opt=1")
ParseResult(scheme='https', netloc='i.cnblogs.com', path='/EditPosts.aspx', params='', query='opt=1', fragment='')

The returned element will also contain other attributes, such as (username, password, hostname, port):

>>> urlparse.urlparse("https://i.cnblogs.com:80/EditPosts.aspx?opt=1").port
80

>>> urlparse.urlparse("https://i.cnblogs.com:80/EditPosts.aspx?opt=1").hostname
'i.cnblogs.com'

2. urlparse.urljoin() (Combines relative addresses into a url. There is no limit on input. The beginning must be Is http://, otherwise the front will not be combined)

>>> urlparse.urljoin("https://i.cnblogs.com","EditPosts.aspx")
'https://i.cnblogs.com/EditPosts.aspx'

3. urlparse.urlsplit(): Returns a tuple of 5 elements , suitable for URLs that follow RFC2396

##

>>> urlparse.urlsplit("https://i.cnblogs.com:80/EditPosts.aspx?opt=1")
SplitResult(scheme='https', netloc='i.cnblogs.com:80', path='/EditPosts.aspx', query='opt=1', fragment='')

4. urlparse.urlunsplit(): Use the urlsplit format to combine into a url, and the passed elements must is 5, or directly reassemble the decomposed tuples

>>> urlparse.urlunsplit(("https","i.cnblogs.com","EditPosts.aspx","a=a","b=b"))
'https://i.cnblogs.com/EditPosts.aspx?a=a#b=b'

>>> parse = urlparse.urlsplit("https://i.cnblogs.com:80/EditPosts.aspx?opt=1")
>>> urlparse.urlunsplit(parse)
'https://i.cnblogs.com:80/EditPosts.aspx?opt=1'

5, urlparse.urlunparse(): Use the format of urlparse to combine into a url, you can directly pass the return combination of urlparse

>>> parse = urlparse.urlparse("https://i.cnblogs.com:80/EditPosts.aspx?opt=1")
>>> urlparse.urlunparse(parse)
'https://i.cnblogs.com:80/EditPosts.aspx?opt=1'

>>> urlparse.urlunparse(("https","i.cnblogs.com","/EditPosts.aspx","","opt=1",""))
'https://i.cnblogs.com/EditPosts.aspx?opt=1'

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