利用datetime模块进行不同时间单位的换算
from datetime import timedelta a = timedelta(days=2, hours=6) b = timedelta(hours=4.5) c = a + b print(c.days) print(c.seconds) print(c.seconds / 3600)
表示特定的日期和时间
from datetime import datetime a = datetime(2016, 8, 30) print(a + timedelta(days=10)) b = datetime(2016, 9, 30) d = b - a print(d.days) now = datetime.today() print(now) print(now + timedelta(minutes=10))
datetime模块可以正确处理闰年
a = datetime(2012, 3, 1) b = datetime(2012, 2, 28) print((a-b).days) c = datetime(2013, 3, 1) d = datetime(2013, 2, 28) print((c-d).days)
处理更为复杂的日期问题,如处理时区,模糊时间范围,计算节日的日期等可以用dateutil模块
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