在这份教程中,我们将会学习到如何组织用户通过PHP上传成人照片或者裸照.
我在phpclasses.org上面偶然发现一个很有用的,由Bakr Alsharif开发的可以帮助开发者基于皮肤像素点来检测图片裸照的类文件.
它会分析在一张图片的不同部分使用的颜色,并决定其是否匹配人类皮肤颜色的色调.
作为分析的结果,他会返回一个反映图片包含裸露的可能性的分值.
此外,他还可以输出被分析的图片,上面对使用给定颜色的肤色的像素进行了标记.
当前它可以对PNG,GIF和JPEG图片进行分析.
PHP
下面展示了如何使用这个PHP类.
让我们先从包含裸体过滤器,nf.php文件开始.
include ('nf.php');
接下来,创建一个新的名叫ImageFilter的类,然后把它放到一个叫做$filter的变量中.
$filter = new ImageFilter;
获取图片的分值并将其放到一个$score变量中.
$score = $filter -> GetScore($_FILES['img']['tmp_name']);
如果图片分值大于或等于60%,那就展示一条(告警)消息.
if($score >= 60){/*Message*/}
下面是所有的PHP代码:
<?php/*Include the Nudity Filter file*/include ('nf.php');/*Create a new class called $filter*/$filter = new ImageFilter;/*Get the score of the image*/$score = $filter -> GetScore($_FILES['img']['tmp_name']);/*If the $score variable is set*/if (isset($score)) {/*If the image contains nudity, display image score and message. Score value if more
than 60%, it is considered an adult image.*/if ($score >= 60) { echo "Image scored " . $score . "%, It seems that you have uploaded a nude picture.";/*If the image doesn't contain nudity*/ } else if ($score < 0) { echo "Congratulations, you have uploaded an non-nude image.";
}
}?>
标记语言
我们可以使用一个基础的HTML表单上传图片.
<form method="post" enctype="multipart/form-data" action="<?php echo $SERVER['PHP_SELF'];?> ">Upload image:
<input type="file" name="img" id="img" /><input type="submit" value="Sumit Image" /></form>
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