查询表主键外键信息的SQL_PHP教程

我的BSOOC里需要一个查询表主键外键信息的SQL，昨晚研究到凌晨1点，终于能实现这个目标：
Oracle:
select o.obj# as objectId, o.name AS tableName, oc.name AS constraintName,
decode(c.type#, 1, 'C', 2, 'P', 3, 'U',
4, 'R', 5, 'V', 6, 'O', 7,'C', '?') as constraintType,
col.name AS columnName

from sys.con$ oc, sys.con$ rc,
sys.obj$ ro,sys.obj$ o, sys.obj$ oi,
sys.cdef$ c,
sys.col$ col, sys.ccol$ cc, sys.attrcol$ ac
where oc.con# = c.con#
and c.obj# = o.obj#
and c.rcon# = rc.con#( )
and c.enabled = oi.obj#( )
and c.robj# = ro.obj#( )
and c.type# != 8
and c.type# != 12 /* don't include log groups */
and c.con# = cc.con#
and cc.obj# = col.obj#
and cc.intcol# = col.intcol#
and cc.obj# = o.obj#
and col.obj# = ac.obj#( )
and col.intcol# = ac.intcol#( )
and o.name = 'your table'

SQL Server:
SELECT sysobjects.id objectId,
OBJECT_NAME(sysobjects.parent_obj) tableName,
sysobjects.name constraintName,
sysobjects.xtype AS constraintType,
syscolumns.name AS columnName
FROM sysobjects INNER JOIN sysconstraints
ON sysobjects.xtype in('C', 'F', 'PK', 'UQ', 'D')
AND sysobjects.id = sysconstraints.constid
LEFT OUTER JOIN syscolumns ON sysconstraints.id = syscolumns.id
WHERE OBJECT_NAME(sysobjects.parent_obj)='your table'

其它数据库还没时间去实现.