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同时操作不同库里表,支持事物吗,mysql解决办法

原创
2016-06-13 12:26:46 1125浏览

同时操作不同库里表,支持事物吗,mysql
MYSQL数据库

有数据库A和数据库B,同时操作A中两张表和B中两张表,支持事物回滚么,都是innodb。。

分两种情况
A库和B库在同一台服务器
A库和B库不在同一台服务器

请教大神
------解决思路----------------------
A库和B库在同一台服务器
A库和B库不在同一台服务器
两个都支持事务。

可以使用分布式事务


public function testAction(){
$goods_id=1;
$goods_name = "大西瓜";
$num = 1;
$rs_order = $this->test->createorder($goods_id,$goods_name,$num);
$rs_goods = $this->test->deduction($goods_id,$num);
if($rs_order['status'] =="success" && $rs_goods['status']=="success"){
$this->test->commitdb($rs_order['XA']);
$this->test->commitdb1($rs_goods['XA']);
}else{
$this->test->rollbackdb($rs_order['XA']);
$this->test->rollbackdb1($rs_goods['XA']);
}

print_r($rs_order);
echo "
";
print_r($rs_goods);
die("dddd");
}

public function createorder($goods_id,$goods_name,$num){
$XA = uniqid("");
$this->_db->query("XA START '$XA'");
$_rs = true;
try {
$data = array();
$data['order_id'] = "V".date("YmdHis");
$data['goods_name'] = $goods_name;
$data['goods_num'] = $num;
$this->_db->insert("temp_orders",$data);
$rs = $this->_db->lastInsertId();
if($rs){
$_rs = true;
}else{
$_rs = false;
}
} catch (Exception $e) {
$_rs = false;
}
$this->_db->query("XA END '$XA'");
if($_rs){
$this->_db->query("XA PREPARE '$XA'");
return array("status"=>"success","XA"=>$XA);
}else{
return array("status"=>"nosuccess","XA"=>$XA);
}
}

public function deduction($id){
$XA = uniqid("");
$this->db1->query("XA START '$XA'");
$last_rs = true;
try {
$sql = "select * from temp_goods where id = '$id' and goods_num>0";
$rs = $this->db1->fetchRow($sql);
if(!empty($rs)){
$sql = "update temp_goods set goods_num = goods_num-1 where id = '$id'";
$rd = $this->db1->query($sql);
if($rd){
$last_rs = true;
}else{
$last_rs = false;
}
}else{
$last_rs = false;;
}
} catch (Exception $e) {
$last_rs = false;;
}
$this->db1->query("XA END '$XA'");

if($last_rs){
$this->db1->query("XA PREPARE '$XA'");
return array("status"=>"success","XA"=>$XA);
}else{
return array("status"=>"nosuccess","XA"=>$XA);
}

}
//提交事务!
public function commitdb($xa){
return $this->_db->query("XA COMMIT '$xa'");
}

//回滚事务
public function rollbackdb($xa){
return $this->_db->query("XA ROLLBACK '$xa'");
}

//提交事务!
public function commitdb1($xa){
return $this->db1->query("XA COMMIT '$xa'");
}

//回滚事务
public function rollbackdb1($xa){
return $this->db1->query("XA ROLLBACK '$xa'");
}


参考:http://javalifuqing.blog.163.com/blog/static/83699035201341645329839/

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