How to Represent Numbers as Alphabetic Characters in Go?

English Alphabetic Representation of a Number

In Go, there are several methods to convert numbers into alphabetic characters.

Rune Conversion

Add the number to the constant 'A' - 1 to convert it to a rune. For instance, 3 becomes 'C', and 23 becomes 'W'.

<code class="go">import "fmt"

func toChar(i int) rune {
    return rune('A' - 1 + i)
}

func main() {
    for _, i := range []int{1, 2, 23, 26} {
        fmt.Printf("%d %q\n", i, toChar(i))
    }
}</code>

String Conversion

To get the alphabetic representation as a string, use:

<code class="go">func toCharStr(i int) string {
    return string('A' - 1 + i)
}

func main() {
    for _, i := range []int{1, 2, 23, 26} {
        fmt.Printf("%d \"%s\"\n", i, toCharStr(i))
    }
}</code>

Cached String Conversion

For repeated conversions, consider caching the strings in an array:

<code class="go">var arr = [...]string{"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M",
    "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"}

func toCharStrArr(i int) string {
    return arr[i-1]
}

func main() {
    for _, i := range []int{1, 2, 23, 26} {
        fmt.Printf("%d \"%s\"\n", i, toCharStrArr(i))
    }
}</code>

String Constant Slicing

Another efficient option is to slice a constant string:

<code class="go">const abc = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"

func toCharStrConst(i int) string {
    return abc[i-1 : i]
}

func main() {
    for _, i := range []int{1, 2, 23, 26} {
        fmt.Printf("%d \"%s\"\n", i, toCharStrConst(i))
    }
}</code>

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