sql 两表之间数据备份复制的sql语句

原创: 2016-06-07 17:48:18 1049浏览

SELECT INTO 语句从一个表中选取数据，然后把数据插入另一个表中。

SELECT INTO 语句常用于创建表的备份复件或者用于对记录进行存档。

SQL SELECT INTO 语法
您可以把所有的列插入新表：

SELECT *
INTO new_table_name [IN externaldatabase]
FROM old_tablename

> create table employee(
2> ID int,
3> name nvarchar (10),
4> salary int,
5> start_date datetime,
6> city nvarchar (10),
7> region char (1))
8> GO
1>
2> insert into employee (ID, name, salary, start_date, city, region)
3> values (1, 'Jason', 40420, '02/01/94', 'New York', 'W')
4> GO

(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (2, 'Robert',14420, '01/02/95', 'Vancouver','N')
3> GO

(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (3, 'Celia', 24020, '12/03/96', 'Toronto', 'W')
3> GO

(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (4, 'Linda', 40620, '11/04/97', 'New York', 'N')
3> GO

(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (5, 'David', 80026, '10/05/98', 'Vancouver','W')
3> GO

(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (6, 'James', 70060, '09/06/99', 'Toronto', 'N')
3> GO

(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (7, 'Alison',90620, '08/07/00', 'New York', 'W')
3> GO

(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (8, 'Chris', 26020, '07/08/01', 'Vancouver','N')
3> GO

(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (9, 'Mary', 60020, '06/09/02', 'Toronto', 'W')
3> GO

(1 rows affected)
1>
2> * from employee
3> GO
ID name salary start_date city region
----------- ---------- ----------- ----------------------- ---------- ------
1 Jason 40420 1994-02-01 00:00:00.000 New York W
2 Robert 14420 1995-01-02 00:00:00.000 Vancouver N
3 Celia 24020 1996-12-03 00:00:00.000 Toronto W
4 Linda 40620 1997-11-04 00:00:00.000 New York N
5 David 80026 1998-10-05 00:00:00.000 Vancouver W
6 James 70060 1999-09-06 00:00:00.000 Toronto N
7 Alison 90620 2000-08-07 00:00:00.000 New York W
8 Chris 26020 2001-07-08 00:00:00.000 Vancouver N
9 Mary 60020 2002-06-09 00:00:00.000 Toronto W

(9 rows affected)
1>
2>
3> SELECT Id, Name
4> INTO Employee_Temp FROM Employee WHERE Id > 1
5> GO

(8 rows affected)
1>
2> SELECT * FROM Employee_Temp
3> GO
Id Name

利用select into 做一个临时表

34> CREATE TABLE works_on (emp_no INTEGER NOT NULL,
35> project_no CHAR(4) NOT NULL,
36> job CHAR (15) NULL,
37> enter_date DATETIME NULL)
38>
39> insert into works_on values (1, 'p1', 'analyst', '1997.10.1')
40> insert into works_on values (1, 'p3', 'manager', '1999.1.1')
41> insert into works_on values (2, 'p2', 'clerk', '1998.2.15')
42> insert into works_on values (2, 'p2', NULL, '1998.6.1')
43> insert into works_on values (3, 'p2', NULL, '1997.12.15')
44> insert into works_on values (4, 'p3', 'analyst', '1998.10.15')
45> insert into works_on values (5, 'p1', 'manager', '1998.4.15')
46> insert into works_on values (6, 'p1', NULL, '1998.8.1')
47> insert into works_on values (7, 'p2', 'clerk', '1999.2.1')
48> insert into works_on values (8, 'p3', 'clerk', '1997.11.15')
49> insert into works_on values (7, 'p1', 'clerk', '1998.1.4')
50> GO

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)
1> select * from works_on
2> GO
emp_no project_no job enter_date
----------- ---------- --------------- -----------------------
1 p1 analyst 1997-10-01 00:00:00.000
1 p3 manager 1999-01-01 00:00:00.000
2 p2 clerk 1998-02-15 00:00:00.000
2 p2 NULL 1998-06-01 00:00:00.000
3 p2 NULL 1997-12-15 00:00:00.000
4 p3 analyst 1998-10-15 00:00:00.000
5 p1 manager 1998-04-15 00:00:00.000
6 p1 NULL 1998-08-01 00:00:00.000
7 p2 clerk 1999-02-01 00:00:00.000
8 p3 clerk 1997-11-15 00:00:00.000
7 p1 clerk 1998-01-04 00:00:00.000

(11 rows affected)
1>
2> -- Remove duplicate data and create a unique index
3>
4> SELECT emp_no, MAX(enter_date) max_date
5> INTO #works_on
6> FROM works_on
7> GROUP BY emp_no
8> HAVING COUNT(*) > 1
9> GO

(3 rows affected)
1> DELETE works_on FROM works_on, #works_on
2> WHERE works_on.emp_no = #works_on.emp_no
3> AND works_on.enter_date < #works_on.max_date
4> GO

(3 rows affected)
1> select * from works_on
2> GO
emp_no project_no job enter_date
----------- ---------- --------------- -----------------------
1 p3 manager 1999-01-01 00:00:00.000
2 p2 NULL 1998-06-01 00:00:00.000
3 p2 NULL 1997-12-15 00:00:00.000
4 p3 analyst 1998-10-15 00:00:00.000
5 p1 manager 1998-04-15 00:00:00.000
6 p1 NULL 1998-08-01 00:00:00.000
7 p2 clerk 1999-02-01 00:00:00.000
8 p3 clerk 1997-11-15 00:00:00.000

(8 rows affected)