asp.net访问网络路径方法(模拟用户登录)

原创
2016-06-06 20:19:32 1078浏览

这篇文章主要介绍了asp.net访问网络路径方法,其实就是模拟用户登录,需要的朋友可以参考下

核心代码:

public class IdentityScope : IDisposable { // obtains user token [DllImport("advapi32.dll", SetLastError = true)] static extern bool LogonUser(string pszUsername, string pszDomain, string pszPassword,int dwLogonType, int dwLogonProvider, ref IntPtr phToken); // closes open handes returned by LogonUser [DllImport("kernel32.dll", CharSet = CharSet.Auto)] extern static bool CloseHandle(IntPtr handle); [DllImport("Advapi32.DLL")] static extern bool ImpersonateLoggedOnUser(IntPtr hToken); [DllImport("Advapi32.DLL")] static extern bool RevertToSelf(); const int LOGON32_PROVIDER_DEFAULT = 0; const int LOGON32_LOGON_NEWCREDENTIALS = 9;//域ò控?中D的?需è要a用?:Interactive = 2 private bool disposed; ///

/// 登?录? /// /// 用?户§名? /// 域ò名?,?如?果?不?在ú域ò中D就í使1用?机ú器÷IP地?址· /// 密ü码? public IdentityScope(string sUsername, string sDomain, string sPassword) { // initialize tokens IntPtr pExistingTokenHandle = new IntPtr(0); IntPtr pDuplicateTokenHandle = new IntPtr(0); try { // get handle to token bool bImpersonated = LogonUser(sUsername, sDomain, sPassword,LOGON32_LOGON_NEWCREDENTIALS, LOGON32_PROVIDER_DEFAULT, ref pExistingTokenHandle); if (true == bImpersonated) { if (!ImpersonateLoggedOnUser(pExistingTokenHandle)) { int nErrorCode = Marshal.GetLastWin32Error(); throw new Exception("ImpersonateLoggedOnUser error;Code=" + nErrorCode); } } else { int nErrorCode = Marshal.GetLastWin32Error(); throw new Exception("LogonUser error;Code=" + nErrorCode); } } finally { // close handle(s) if (pExistingTokenHandle != IntPtr.Zero) CloseHandle(pExistingTokenHandle); if (pDuplicateTokenHandle != IntPtr.Zero) CloseHandle(pDuplicateTokenHandle); } } protected virtual void Dispose(bool disposing) { if (!disposed) { RevertToSelf(); disposed = true; } } public void Dispose() { Dispose(true); } }

第二个参数是域名,有域名的话写域名,,没有域名写目标机器的IP就可以了

using (IdentityScope c = new IdentityScope("administrator", "192.168.0.1", "11111")) { string[] filelist = System.IO.Directory.GetDirectories(@"\\192.168.0.1\folderName"); }

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