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    python实现提取百度搜索结果的方法

    2016-06-06 11:16:44原创1051
    本文实例讲述了python实现提取百度搜索结果的方法。分享给大家供大家参考。具体实现方法如下:

    # coding=utf8
    import urllib2
    import string
    import urllib
    import re
    import random
    #设置多个user_agents,防止百度限制IP
    user_agents = ['Mozilla/5.0 (Windows NT 6.1; WOW64; rv:23.0) Gecko/20130406 Firefox/23.0', \
        'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:18.0) Gecko/20100101 Firefox/18.0', \
        'Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US) AppleWebKit/533+ \
        (KHTML, like Gecko) Element Browser 5.0', \
        'IBM WebExplorer /v0.94', 'Galaxy/1.0 [en] (Mac OS X 10.5.6; U; en)', \
        'Mozilla/5.0 (compatible; MSIE 10.0; Windows NT 6.1; WOW64; Trident/6.0)', \
        'Opera/9.80 (Windows NT 6.0) Presto/2.12.388 Version/12.14', \
        'Mozilla/5.0 (iPad; CPU OS 6_0 like Mac OS X) AppleWebKit/536.26 (KHTML, like Gecko) \
        Version/6.0 Mobile/10A5355d Safari/8536.25', \
        'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) \
        Chrome/28.0.1468.0 Safari/537.36', \
        'Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.0; Trident/5.0; TheWorld)']
    def baidu_search(keyword,pn):
      p= {'wd': keyword} 
      res=urllib2.urlopen(("http://www.baidu.com/s?"+urllib.urlencode(p)+"&pn={0}&cl=3&rn=100").format(pn))
      html=res.read()
      return html
    def getList(regex,text):
      arr = []
      res = re.findall(regex, text)
      if res:
        for r in res:
          arr.append(r)
      return arr
    def getMatch(regex,text):
      res = re.findall(regex, text)
      if res:
        return res[0]
      return ""
    def clearTag(text):
      p = re.compile(u'<[^>]+>')
      retval = p.sub("",text)
      return retval
    def geturl(keyword):
      for page in range(10):
        pn=page*100+1
        html = baidu_search(keyword,pn)
        content = unicode(html, 'utf-8','ignore')
        arrList = getList(u".*?<\/a>", content)
        for item in arrList:
          regex = u"(.*?)<\/a>"
          link = getMatch(regex,item)
          url = link[0]
          #获取标题
          #title = clearTag(link[1]).encode('utf8')
          try:
            domain=urllib2.Request(url)
            r=random.randint(0,11)
            domain.add_header('User-agent', user_agents[r])
            domain.add_header('connection','keep-alive')
            response=urllib2.urlopen(domain)
            uri=response.geturl()
            print uri
          except:
            continue
    if __name__=='__main__':
      geturl('python')

    希望本文所述对大家的Python程序设计有所帮助。

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