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    Mysql之 详解JOIN

    coldplay.xixicoldplay.xixi2020-12-04 14:45:56转载675

    mysql视频教程栏目详解join

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    0 索引

    • JOIN语句的执行顺序
    • INNER/LEFT/RIGHT/FULL JOIN的区别
    • ONWHERE的区别

    1 概述

    一个完整的SQL语句中会被拆分成多个子句,子句的执行过程中会产生虚拟表(vt),但是结果只返回最后一张虚拟表。从这个思路出发,我们试着理解一下JOIN查询的执行过程并解答一些常见的问题。
    如果之前对不同JOIN的执行结果没有概念,可以结合这篇文章往下看

    2 JOIN的执行顺序

    以下是JOIN查询的通用结构

    SELECT <row_list> 
      FROM <left_table> 
        <inner|left|right> JOIN <right_table> 
          ON <join condition> 
            WHERE <where_condition>

    它的执行顺序如下(SQL语句里第一个被执行的总是FROM子句)

    下面用一个例子介绍一下上述联表的过程(这个例子不是个好的实践,只是为了说明join语法)

    3 举例

    创建一个用户信息表:

    CREATE TABLE `user_info` (
      `userid` int(11) NOT NULL,
      `name` varchar(255) NOT NULL,
      UNIQUE `userid` (`userid`)
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4

    再创建一个用户余额表:

    CREATE TABLE `user_account` (
      `userid` int(11) NOT NULL,
      `money` bigint(20) NOT NULL,
     UNIQUE `userid` (`userid`)
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4

    随便导入一些数据:

    select * from user_info;
    +--------+------+
    | userid | name |
    +--------+------+
    |   1001 | x    |
    |   1002 | y    |
    |   1003 | z    |
    |   1004 | a    |
    |   1005 | b    |
    |   1006 | c    |
    |   1007 | d    |
    |   1008 | e    |
    +--------+------+
    8 rows in set (0.00 sec)
    
    select * from user_account;
    +--------+-------+
    | userid | money |
    +--------+-------+
    |   1001 |    22 |
    |   1002 |    30 |
    |   1003 |     8 |
    |   1009 |    11 |
    +--------+-------+
    4 rows in set (0.00 sec)

    一共8个用户有用户名,4个用户的账户有余额。
    取出userid为1003的用户姓名和余额,SQL如下

    SELECT i.name, a.money 
      FROM user_info as i 
        LEFT JOIN user_account as a 
          ON i.userid = a.userid 
            WHERE a.userid = 1003;

    第一步:执行FROM子句对两张表进行笛卡尔积操作

    笛卡尔积操作后会返回两张表中所有行的组合,左表user_info有8行,右表user_account有4行,生成的虚拟表vt1就是8*4=32行:

    SELECT * FROM user_info as i LEFT JOIN user_account as a ON 1;
    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1001 | x    |   1001 |    22 |
    |   1002 | y    |   1001 |    22 |
    |   1003 | z    |   1001 |    22 |
    |   1004 | a    |   1001 |    22 |
    |   1005 | b    |   1001 |    22 |
    |   1006 | c    |   1001 |    22 |
    |   1007 | d    |   1001 |    22 |
    |   1008 | e    |   1001 |    22 |
    |   1001 | x    |   1002 |    30 |
    |   1002 | y    |   1002 |    30 |
    |   1003 | z    |   1002 |    30 |
    |   1004 | a    |   1002 |    30 |
    |   1005 | b    |   1002 |    30 |
    |   1006 | c    |   1002 |    30 |
    |   1007 | d    |   1002 |    30 |
    |   1008 | e    |   1002 |    30 |
    |   1001 | x    |   1003 |     8 |
    |   1002 | y    |   1003 |     8 |
    |   1003 | z    |   1003 |     8 |
    |   1004 | a    |   1003 |     8 |
    |   1005 | b    |   1003 |     8 |
    |   1006 | c    |   1003 |     8 |
    |   1007 | d    |   1003 |     8 |
    |   1008 | e    |   1003 |     8 |
    |   1001 | x    |   1009 |    11 |
    |   1002 | y    |   1009 |    11 |
    |   1003 | z    |   1009 |    11 |
    |   1004 | a    |   1009 |    11 |
    |   1005 | b    |   1009 |    11 |
    |   1006 | c    |   1009 |    11 |
    |   1007 | d    |   1009 |    11 |
    |   1008 | e    |   1009 |    11 |
    +--------+------+--------+-------+
    32 rows in set (0.00 sec)

    第二步:执行ON子句过滤掉不满足条件的行

    ON i.userid = a.userid 过滤之后vt2如下:

    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1001 | x    |   1001 |    22 |
    |   1002 | y    |   1002 |    30 |
    |   1003 | z    |   1003 |     8 |
    +--------+------+--------+-------+

    第三步:JOIN 添加外部行

    LEFT JOIN会将左表未出现在vt2的行插入进vt2,每一行的剩余字段将被填充为NULL,RIGHT JOIN同理
    本例中用的是LEFT JOIN,所以会将左表user_info剩下的行都添上 生成表vt3:

    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1001 | x    |   1001 |    22 |
    |   1002 | y    |   1002 |    30 |
    |   1003 | z    |   1003 |     8 |
    |   1004 | a    |   NULL |  NULL |
    |   1005 | b    |   NULL |  NULL |
    |   1006 | c    |   NULL |  NULL |
    |   1007 | d    |   NULL |  NULL |
    |   1008 | e    |   NULL |  NULL |
    +--------+------+--------+-------+

    第四步:WHERE条件过滤

    WHERE a.userid = 1003 生成表vt4:

    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1003 | z    |   1003 |     8 |
    +--------+------+--------+-------+

    第五步:SELECT

    SELECT i.name, a.money 生成vt5:

    +------+-------+
    | name | money |
    +------+-------+
    | z    |     8 |
    +------+-------+

    虚拟表vt5作为最终结果返回给客户端

    介绍完联表的过程之后,我们看看常用JOIN的区别

    4 INNER/LEFT/RIGHT/FULL JOIN的区别

    INNER JOIN

    拿上文的第三步添加外部行来举例,若LEFT JOIN替换成INNER JOIN,则会跳过这一步,生成的表vt3与vt2一模一样:

    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1001 | x    |   1001 |    22 |
    |   1002 | y    |   1002 |    30 |
    |   1003 | z    |   1003 |     8 |
    +--------+------+--------+-------+

    RIGHT JOIN

    LEFT JOIN替换成RIGHT JOIN,则生成的表vt3如下:

    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1001 | x    |   1001 |    22 |
    |   1002 | y    |   1002 |    30 |
    |   1003 | z    |   1003 |     8 |
    |   NULL | NULL |   1009 |    11 |
    +--------+------+--------+-------+

    因为user_account(右表)里存在userid=1009这一行,而user_info(左表)里却找不到这一行的记录,所以会在第三步插入以下一行:

    |   NULL | NULL |   1009 |    11 |

    FULL JOIN

    上文引用的文章中提到了标准SQL定义的FULL JOIN,这在mysql里是不支持的,不过我们可以通过LEFT JOIN + UNION + RIGHT JOIN 来实现FULL JOIN

    SELECT * 
      FROM user_info as i 
        RIGHT JOIN user_account as a 
          ON a.userid=i.userid
    union 
    SELECT * 
      FROM user_info as i 
        LEFT JOIN user_account as a 
          ON a.userid=i.userid;

    他会返回如下结果:

    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1001 | x    |   1001 |    22 |
    |   1002 | y    |   1002 |    30 |
    |   1003 | z    |   1003 |     8 |
    |   NULL | NULL |   1009 |    11 |
    |   1004 | a    |   NULL |  NULL |
    |   1005 | b    |   NULL |  NULL |
    |   1006 | c    |   NULL |  NULL |
    |   1007 | d    |   NULL |  NULL |
    |   1008 | e    |   NULL |  NULL |
    +--------+------+--------+-------+

    ps:其实我们从语义上就能看出LEFT JOINRIGHT JOIN没什么差别,两者的结果差异取决于左右表的放置顺序,以下内容摘自mysql官方文档:

    RIGHT JOIN works analogously to LEFT JOIN. To keep code portable across databases, it is recommended that you use LEFT JOIN instead of RIGHT JOIN.

    所以当你纠结使用LEFT JOIN还是RIGHT JOIN时,尽可能只使用LEFT JOIN吧

    5 ON和WHERE的区别

    上文把JOIN的执行顺序了解清楚之后,ON和WHERE的区别也就很好理解了。
    举例说明:

    SELECT * 
      FROM user_info as i
        LEFT JOIN user_account as a
          ON i.userid = a.userid and i.userid = 1003;
    SELECT * 
      FROM user_info as i
        LEFT JOIN user_account as a
          ON i.userid = a.userid where i.userid = 1003;

    第一种情况LEFT JOIN在执行完第二步ON子句后,筛选出满足i.userid = a.userid and i.userid = 1003的行,生成表vt2,然后执行第三步JOIN子句,将外部行添加进虚拟表生成vt3即最终结果:

    vt2:
    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1003 | z    |   1003 |     8 |
    +--------+------+--------+-------+
    vt3:
    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1001 | x    |   NULL |  NULL |
    |   1002 | y    |   NULL |  NULL |
    |   1003 | z    |   1003 |     8 |
    |   1004 | a    |   NULL |  NULL |
    |   1005 | b    |   NULL |  NULL |
    |   1006 | c    |   NULL |  NULL |
    |   1007 | d    |   NULL |  NULL |
    |   1008 | e    |   NULL |  NULL |
    +--------+------+--------+-------+

    而第二种情况LEFT JOIN在执行完第二步ON子句后,筛选出满足i.userid = a.userid的行,生成表vt2;再执行第三步JOIN子句添加外部行生成表vt3;然后执行第四步WHERE子句,再对vt3表进行过滤生成vt4,得的最终结果:

    vt2:
    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1001 | x    |   1001 |    22 |
    |   1002 | y    |   1002 |    30 |
    |   1003 | z    |   1003 |     8 |
    +--------+------+--------+-------+
    vt3:
    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1001 | x    |   1001 |    22 |
    |   1002 | y    |   1002 |    30 |
    |   1003 | z    |   1003 |     8 |
    |   1004 | a    |   NULL |  NULL |
    |   1005 | b    |   NULL |  NULL |
    |   1006 | c    |   NULL |  NULL |
    |   1007 | d    |   NULL |  NULL |
    |   1008 | e    |   NULL |  NULL |
    +--------+------+--------+-------+
    vt4:
    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1003 | z    |   1003 |     8 |
    +--------+------+--------+-------+

    如果将上例的LEFT JOIN替换成INNER JOIN,不论将条件过滤放到ON还是WHERE里,结果都是一样的,因为INNER JOIN不会执行第三步添加外部行

    SELECT * 
      FROM user_info as i
        INNER JOIN user_account as a
          ON i.userid = a.userid and i.userid = 1003;
    SELECT * 
      FROM user_info as i
        INNER JOIN user_account as a
          ON i.userid = a.userid where i.userid = 1003;

    返回结果都是:

    +--------+------+--------+-------+
    | userid | name | userid | money |
    +--------+------+--------+-------+
    |   1003 | z    |   1003 |     8 |
    +--------+------+--------+-------+

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