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    C++解决方法:多线程同步经典案例之生产者消费者问题

    php是最好的语言php是最好的语言2018-08-06 13:56:38原创1998
    抄自维基百科 :

    生产者消费者问题(英语:Producer-consumer problem),也称有限缓冲问题(英语:Bounded-buffer problem),是一个多线程同步问题的经典案例。该问题描述了共享固定大小缓冲区的两个线程——即所谓的“生产者”和“消费者”——在实际运行时会发生的问题。生产者的主要作用是生成一定量的数据放到缓冲区中,然后重复此过程。与此同时,消费者也在缓冲区消耗这些数据。该问题的关键就是要保证生产者不会在缓冲区满时加入数据,消费者也不会在缓冲区中空时消耗数据。

    要解决该问题,就必须让生产者在缓冲区满时休眠(要么干脆就放弃数据),等到下次消费者消耗缓冲区中的数据的时候,生产者才能被唤醒,开始往缓冲区添加数据。同样,也可以让消费者在缓冲区空时进入休眠,等到生产者往缓冲区添加数据之后,再唤醒消费者。

    本文用一个ItemRepository类表示产品仓库,其中包含一个数组和两个坐标表示的环形队列、一个std::mutex成员、用来保证每次只被一个线程读写操作 (为了保证打印出来的消息是一行一行的,在它空闲的时候也借用的这个互斥量╮(╯▽╰)╭)、两个std::condition_variable表示队列不满和不空的状态,进而保证生产的时候不满,消耗的时候不空。

    #pragma once
    #include <chrono>//std::chrono
    #include <mutex>//std::mutex,std::unique_lock,std::lock_guard
    #include <thread>//std::thread
    #include <condition_variable>//std::condition_variable
    #include <iostream>//std::cout,std::endl
    #include <map>//std::map
    namespace MyProducerToConsumer {
        static const int gRepositorySize = 10;//total size of the repository
        static const int gItemNum = 97;//number of products to produce
        std::mutex produce_mtx, consume_mtx;//mutex for all the producer thread or consumer thread
        std::map<std::thread::id, int> threadPerformance;//records of every thread's producing/consuming number
        struct ItemRepository {//repository class
            int m_ItemBuffer[gRepositorySize];//Repository itself (as a circular queue)
            int m_ProducePos;//rear position of circular queue
            int m_ConsumePos;//head position of circular queue
            std::mutex m_mtx;//mutex for operating the repository
            std::condition_variable m_RepoUnfull;//indicating that this repository is unfull(then producers can produce items)
            std::condition_variable m_RepoUnempty;//indicating that this repository is unempty(then consumers can produce items)
        }gItemRepo;
    
        void ProduceItem(ItemRepository *ir, int item) {
            std::unique_lock <std::mutex>ulk(ir->m_mtx);
            while ((ir->m_ProducePos + 1) % gRepositorySize == ir->m_ConsumePos) {//full(spare one slot for indicating)
                std::cout << "Reposity is full. Waiting for consumers..." << std::endl;
                ir->m_RepoUnfull.wait(ulk);//unlocking ulk and waiting for unfull condition
            }
            //when unfull
            ir->m_ItemBuffer[ir->m_ProducePos++] = item;//procude and shift
            std::cout << "Item No." << item << " produced successfully by "
                <<std::this_thread::get_id()<<"!" << std::endl;
            threadPerformance[std::this_thread::get_id()]++;
            if (ir->m_ProducePos == gRepositorySize)//loop
                ir->m_ProducePos = 0;
            ir->m_RepoUnempty.notify_all();//item produced, so it's unempty; notify all consumers
        }
    
        int ConsumeItem(ItemRepository *ir) {
            std::unique_lock<std::mutex>ulk(ir->m_mtx);
            while (ir->m_ConsumePos == ir->m_ProducePos) {//empty
                std::cout << "Repository is empty.Waiting for producing..." << std::endl;
                ir->m_RepoUnempty.wait(ulk);
            }
            int item = ir->m_ItemBuffer[ir->m_ConsumePos++];
            std::cout << "Item No." << item << " consumed successfully by "
                <<std::this_thread::get_id()<<"!" << std::endl;
            threadPerformance[std::this_thread::get_id()]++;
            if (ir->m_ConsumePos == gRepositorySize)
                ir->m_ConsumePos = 0;
            ir->m_RepoUnfull.notify_all();//item consumed, so it's unempty; notify all consumers
            return item;
        }
    
        void ProducerThread() {
            static int produced = 0;//static variable to indicate the number of produced items
            while (1) {
                std::this_thread::sleep_for(std::chrono::milliseconds(10));//sleep long enough in case it runs too fast for other threads to procude
                std::lock_guard<std::mutex>lck(produce_mtx);//auto unlock when break
                produced++;
                if (produced > gItemNum)break;
                gItemRepo.m_mtx.lock();
                std::cout << "Producing item No." << produced << "..." << std::endl;
                gItemRepo.m_mtx.unlock();
                ProduceItem(&gItemRepo, produced);
            }
            gItemRepo.m_mtx.lock();
            std::cout << "Producer thread " << std::this_thread::get_id()
                << " exited." << std::endl;
            gItemRepo.m_mtx.unlock();
        }
    
        void ConsumerThread() {
            static int consumed = 0;
            while (1) {
                std::this_thread::sleep_for(std::chrono::milliseconds(10));
                std::lock_guard<std::mutex>lck(consume_mtx);
                consumed++;
                if (consumed > gItemNum)break;
                gItemRepo.m_mtx.lock();
                std::cout << "Consuming item available..." << std::endl;
                gItemRepo.m_mtx.unlock();
                ConsumeItem(&gItemRepo);
            }
            gItemRepo.m_mtx.lock();
            std::cout << "Consumer thread " << std::this_thread::get_id()
                << " exited." << std::endl;
            gItemRepo.m_mtx.unlock();
        }
    
        void InitItemRepository(ItemRepository* ir) {
            ir->m_ConsumePos = 0;
            ir->m_ProducePos = 0;
        }
    
        void Run() {
            InitItemRepository(&gItemRepo);
            std::thread thdConsume[11];
            std::thread thdProduce[11];
            for (auto& t : thdConsume)t = std::thread(ConsumerThread);
            for (auto& t : thdProduce)t = std::thread(ProducerThread);
            for (auto& t : thdConsume)t.join();
            for (auto& t : thdProduce)t.join();
            for (auto& iter : threadPerformance)cout << iter.first << ":" << iter.second << endl;
        }
    }

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  • Pilgrim

    您好,我试了一下,最后一行代码cout和endl那里报错,我试了一下std::cout也报错为什么呀

    2021-07-19

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