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    MYSQL查询时间数据

    jacklovejacklove2018-06-08 10:22:11原创923
    利用mysql查询时间数据在平常使用php中经常会遇到,本篇将介绍多种时间数据的查询。

    mysql查询本季度

    今天

    select * from 表名 where to_days(时间字段名) = to_days(now());

    昨天

    SELECT *FROM表名WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 时间字段名) <= 1

    7天

    SELECT *FROM表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

    近30天

    SELECT *FROM表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

    本月

    SELECT *FROM表名 WHERE DATE_FORMAT( 时间字段名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )

    上一月

    SELECT *FROM表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 时间字段名, ‘%Y%m’ ) ) =1
    #查询本季度数据
    select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
    #查询上季度数据
    select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
    #查询本年数据
    select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
    #查询上年数据
    select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
    查询当前这周的数据
    SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now());
    查询上周的数据
    SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now())-1;
    查询当前月份的数据
    select name,submittime from enterprisewhere date_format(submittime,’%Y-%m’)=date_format(now(),’%Y-%m’)
    查询距离当前现在6个月的数据
    select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
    查询上个月的数据
    select name,submittime from enterprisewhere date_format(submittime,’%Y-%m’)=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),’%Y-%m’)
    select*from`user`whereDATE_FORMAT(pudate,‘%Y%m‘)=DATE_FORMAT(CURDATE(),‘%Y%m‘) ;
    select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,’%y-%m-%d’)) = WEEKOFYEAR(now())
    select*
    fromuser
    whereMONTH(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=MONTH(now())
    select*
    from[user]
    whereYEAR(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=YEAR(now())
    andMONTH(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=MONTH(now())
    select*
    from[user]
    wherepudatebetween上月最后一天
    and下月第一天
    wheredate(regdate)=curdate();
    select*fromtestwhereyear(regdate)=year(now())andmonth(regdate)=month(now())andday(regdate)=day(now())
    SELECT date( c_instime ) ,curdate( )FROM `t_score`WHERE 1LIMIT 0 , 30

    本文介绍了多个常用到的时间数据,更多相关内容请关注php中文网。

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