详解python用模块zlib压缩与解压字符串和文件的方法代码

import zlib
message = 'abcd1234'
compressed = zlib.compress(message)
decompressed = zlib.decompress(compressed)
print 'original:', repr(message)
print 'compressed:', repr(compressed)
print 'decompressed:', repr(decompressed)

结果

original: 'abcd1234'
compressed: 'x\x9cKLJN1426\x01\x00\x0b\xf8\x02U'
decompressed: 'abcd1234'

例子2：压缩与解压文件

import zlib
def compress(infile, dst, level=9):
 infile = open(infile, 'rb')
 dst = open(dst, 'wb')
 compress = zlib.compressobj(level)
 data = infile.read(1024)
 while data:
  dst.write(compress.compress(data))
  data = infile.read(1024)
 dst.write(compress.flush())
def decompress(infile, dst):
 infile = open(infile, 'rb')
 dst = open(dst, 'wb')
 decompress = zlib.decompressobj()
 data = infile.read(1024)
 while data:
  dst.write(decompress.decompress(data))
  data = infile.read(1024)
 dst.write(decompress.flush())
if __name__ == "__main__":
 compress('in.txt', 'out.txt')
 decompress('out.txt', 'out_decompress.txt')

结果
生成文件

out_decompress.txt out.txt

问题――处理对象过大异常

>>> import zlib
>>> a = '123'
>>> b = zlib.compress(a)
>>> b
'x\x9c342\x06\x00\x01-\x00\x97'
>>> a = 'a' * 1024 * 1024 * 1024 * 10
>>> b = zlib.compress(a)
Traceback (most recent call last):
 File "<stdin>", line 1, in <module>
OverflowError: size does not fit in an int

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