• 技术文章 >后端开发 >php教程

    分享PHP计算两个日期相差天数的代码_php技巧

    2016-05-16 20:02:09原创1157

    本文实例讲述了php计算两个日期相差天数的方法。分享给大家供大家参考。具体实现方法如下:

    <?php
    $date1 = date( 'Y-m-d' );
    $date2 = "2015-12-04";
    $diff = abs(strtotime($date2) - strtotime($date1));
    $years = floor($diff / (365*60*60*24));
    $months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
    $days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
    printf("%d years, %d months, %d days\n", $years, $months, $days);
    -------------------------------------------------------- OR
    $date1 = new DateTime("2007-03-24");
    $date2 = new DateTime("2009-06-26");
    $interval = $date1->diff($date2);
    echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days "; 
    // shows the total amount of days (not divided into years, months and days like above)
    echo "difference " . $interval->days . " days ";
    -------------------------------------------------------- OR  
      
    /**
     * Calculate differences between two dates with precise semantics. Based on PHPs DateTime::diff()
     * implementation by Derick Rethans. Ported to PHP by Emil H, 2011-05-02. No rights reserved.
    */
    function _date_range_limit($start, $end, $adj, $a, $b, $result)
    {
     if ($result[$a] < $start) {
      $result[$b] -= intval(($start - $result[$a] - 1) / $adj) + 1;
      $result[$a] += $adj * intval(($start - $result[$a] - 1) / $adj + 1);
     }
     if ($result[$a] >= $end) {
      $result[$b] += intval($result[$a] / $adj);
      $result[$a] -= $adj * intval($result[$a] / $adj);
     }
     return $result;
    }
    function _date_range_limit_days($base, $result)
    {
     $days_in_month_leap = array(31, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
     $days_in_month = array(31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
     _date_range_limit(1, 13, 12, "m", "y", &$base);
     $year = $base["y"];
     $month = $base["m"];
     if (!$result["invert"]) {
      while ($result["d"] < 0) {
       $month--;
       if ($month < 1) {
        $month += 12;
        $year--;
       }
       $leapyear = $year % 400 == 0 || ($year % 100 != 0 && $year % 4 == 0);
       $days = $leapyear ? $days_in_month_leap[$month] : $days_in_month[$month];
       $result["d"] += $days;
       $result["m"]--;
      }
     } else {
      while ($result["d"] < 0) {
       $leapyear = $year % 400 == 0 || ($year % 100 != 0 && $year % 4 == 0);
       $days = $leapyear ? $days_in_month_leap[$month] : $days_in_month[$month];
       $result["d"] += $days;
       $result["m"]--;
       $month++;
       if ($month > 12) {
        $month -= 12;
        $year++;
       }
      }
     }
     return $result;
    }
    function _date_normalize($base, $result)
    {
     $result = _date_range_limit(0, 60, 60, "s", "i", $result);
     $result = _date_range_limit(0, 60, 60, "i", "h", $result);
     $result = _date_range_limit(0, 24, 24, "h", "d", $result);
     $result = _date_range_limit(0, 12, 12, "m", "y", $result);
     $result = _date_range_limit_days(&$base, &$result);
     $result = _date_range_limit(0, 12, 12, "m", "y", $result);
     return $result;
    }
    /**
     * Accepts two unix timestamps.
     */
    function _date_diff($one, $two)
    {
     $invert = false;
     if ($one > $two) {
      list($one, $two) = array($two, $one);
      $invert = true;
     }
     $key = array("y", "m", "d", "h", "i", "s");
     $a = array_combine($key, array_map("intval", explode(" ", date("Y m d H i s", $one))));
     $b = array_combine($key, array_map("intval", explode(" ", date("Y m d H i s", $two))));
     $result = array();
     $result["y"] = $b["y"] - $a["y"];
     $result["m"] = $b["m"] - $a["m"];
     $result["d"] = $b["d"] - $a["d"];
     $result["h"] = $b["h"] - $a["h"];
     $result["i"] = $b["i"] - $a["i"];
     $result["s"] = $b["s"] - $a["s"];
     $result["invert"] = $invert ? 1 : 0;
     $result["days"] = intval(abs(($one - $two)/86400));
     if ($invert) {
      _date_normalize(&$a, &$result);
     } else {
      _date_normalize(&$b, &$result);
     }
     return $result;
    }
    $date = "2014-12-04 19:37:22";
    echo '
    ';
    print_r( _date_diff( strtotime($date), time() ) );
    echo '
    '; ?>

    希望本文所述对大家学习php程序设计有所帮助。

    声明:本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系admin@php.cn核实处理。
    专题推荐:PHP 日期 天数
    上一篇:配置eAccelerator和XCache扩展来加速PHP程序的执行_php技巧 下一篇:自己动手写 PHP MVC 框架(40节精讲/巨细/新人进阶必看)

    相关文章推荐

    • 一文解析PHP元转分的错误示范(附代码实例)• PHP+Socket系列之实现websocket聊天室• PHP+Socket系列之IO多路复用及实现web服务器• PHP+Socket系列之实现客户端与服务端数据传输• 聊聊PHP escapeshellarg函数使用的中文问题
    1/1

    PHP中文网