• 技术文章 >后端开发 >php教程

    关于处置数组中同类统计的解决方案(PHP)

    2016-06-13 10:50:00原创268
    关于处理数组中同类统计的解决方案(PHP)

    $arrItem = array(
    Array (10000,'中国',1),
    Array (10000,'中国',3),
    Array (20000,'美国',2),
    Array (30000,'法国',5)
    );

    $arr = array();
    foreach($arrItem as $v){
    ??? $arr[$v[0]] = isset($arr[$v[0]]) ? $arr[$v[0]] + $v[2] : $v[2];
    ??? print_r($arr);
    ??? echo '
    ';
    }

    ?

    ?

    ?

    $arr = array(
    ??? array('countyid' => 1, 'county' => '中国', 'province' => '湖南'),
    ??? array('countyid' => 1, 'county' => '中国', 'province' => '湖南'),
    ??? array('countyid' => 3, 'county' => '日本', 'province' => '名古屋'),
    ??? array('countyid' => 3, 'county' => '日本', 'province' => '东京'),
    ??? array('countyid' => 1, 'county' => '中国', 'province' => '北京'),
    ??? array('countyid' => 1, 'county' => '中国', 'province' => '山东'),
    ??? array('countyid' => 1, 'county' => '中国', 'province' => '山东'),
    ??? array('countyid' => 2, 'county' => '美国', 'province' => '安大略'),
    ??? array('countyid' => 2, 'county' => '美国', 'province' => '安大略'),
    ??? array('countyid' => 3, 'county' => '日本', 'province' => '名古屋'),
    );

    $countyGroupCount = array();
    $countyProvinceGroupCount = array();

    foreach ($arr as $row) {
    ??? $countyKey = $row['county'];
    ??? $countyProvinceKey = $row['county'] . '-' . $row['province'];

    ??? if (!isset($countyGroupCount[$countyKey])) {
    ??????? $countyGroupCount[$countyKey] = 1;
    ??? } else {
    ??????? $countyGroupCount[$countyKey] += 1;
    ??? }

    ??? if (!isset($countyProvinceGroupCount[$countyProvinceKey])) {
    ??????? $countyProvinceGroupCount[$countyProvinceKey] = 1;
    ??? } else {
    ??????? $countyProvinceGroupCount[$countyProvinceKey] += 1;
    ??? }
    }

    print_r($countyGroupCount);
    print_r($countyProvinceGroupCount);

    声明:本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系admin@php.cn核实处理。
    上一篇:java软件工程师学php -16 exception处理 下一篇:php输出上载到桌面的桌面图标
    千万级数据并发解决方案

    相关文章推荐

    • mysql-在Windows32进行自定义环境搭建测试PHP连接MySQL时总是提示Fatal error: Call to undefined function• Zend Framework入门知识点小结_php实例• CodeIgniter视图使用注意事项_php实例• PHP验证码生成原理和实现_php实例• PHP编程开发怎么提高编程效率 提高PHP编程技术_php实例
    1/1

    PHP中文网