SELECT COUNT(*) AS num FROM lzh_cds c LEFT JOIN lzh_rds r ON c.rd_id=r.rd_id LEFT JOIN lzh_borrowers b ON c.borrowers_id=b.id
WHERE c.isdeleted = 1 AND c.cd_id LIKE '%李四%' OR c.cd_no LIKE '%李四%' OR b.name LIKE '%李四%' OR r.rd_no LIKE '%李四%' AND c.status=6;
为什么这条复合查询语句 c.isdeleted = 1 c.status=6 并没有起作用啊，查询出来的数据只有模糊结果
![[웹 프런트엔드] Node.js 빠른 시작](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
一个where语句中同时出现条件的“与”或者“或的时候”，要将多个OR用小括号括起来再和AND进行“与”，或者将多个AND用小括号括起来再与OR进行“或”