C++로 작성하여 합이 K보다 작은 하위 배열의 수를 찾습니다.

Input : arr[] = {1, 11, 2, 3, 15}
K = 10
Output : 4
{1}, {2}, {3} and {2, 3}

#include <bits/stdc++.h>
using namespace std;
int main(){
    int arr[] = {1, 11, 2, 3, 15}; // given array
    int k = 10; // given k
    int size = sizeof(arr) / sizeof(int); // size of our array.
    int ans = 0; // counter variable.
    for(int i = 0; i < size; i++){ // outer loop.
        int sum = 0;
        for(int j = i; j < size; j++){ // inner loop.
            sum = sum + arr[j];
            if(sum < k) // comparing with k.
               ans++; // incrementing our ans if sum is less than k.
        }
    }
    cout << ans << "\n";
    return 0;
}

#include <bits/stdc++.h>
using namespace std;
int main(){
    int arr[] = {1, 11, 2, 3, 15}; // given array
    int k = 10; // given k
    int size = sizeof(arr) / sizeof(int); // size of our array.
    int ans = 0; // counter variable.
    int start = 0; // left border.
    int end = 0; // right border.
    int sum = 0;
    while(end < size && start < size){ // till the whole array is traversed.
        while(sum >= k && start < end){
           sum = sum - arr[start];
           start++;
        }
        if(end >= start)
           ans = ans + end - start;
        sum += arr[end];
        end++;
    }
    cout << ans << "\n";
    return 0;
}