Python을 사용하여 CMS 시스템의 이미지 관리 기능을 작성하는 방법

from flask import Flask, render_template, request
from flask_sqlalchemy import SQLAlchemy
from PIL import Image

app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///images.db'
db = SQLAlchemy(app)

class Image(db.Model):
    id = db.Column(db.Integer, primary_key=True)
    title = db.Column(db.String(80))
    filename = db.Column(db.String(80))

@app.route('/upload', methods=['POST'])
def upload():
    file = request.files.get("image")
    if file:
        img = Image.open(file)
        img.save("uploads/" + file.filename)
        image = Image(title=request.form.get("title"), filename=file.filename)
        db.session.add(image)
        db.session.commit()
        return "Upload successful!"
    else:
        return "Upload failed!"

@app.route('/images')
def images():
    images = Image.query.all()
    return render_template('images.html', images=images)


@app.route('/image/<int:image_id>')
def image_detail(image_id):
    image = Image.query.get(image_id)
    return render_template('image_detail.html', image=image)

@app.route('/delete/<int:image_id>')
def delete_image(image_id):
    image = Image.query.get(image_id)
    db.session.delete(image)
    db.session.commit()
    return redirect('/images')

<!-- images.html -->
{% for image in images %}
<div>
    <img src="{{ url_for('static', filename='uploads/' + image.filename) }}" alt="{{ image.title }}">
    <a href="{{ url_for('image_detail', image_id=image.id) }}">View details</a>
    <a href="{{ url_for('delete_image', image_id=image.id) }}">Delete</a>
</div>
{% endfor %}

<!-- image_detail.html -->
<h1>{{ image.title }}</h1>
<img src="{{ url_for('static', filename='uploads/' + image.filename) }}" alt="{{ image.title }}">