Python 목록 관련 작업 및 중첩의 기본을 이해하는 데 도움이 되는 문서

   #定义变量A，默认有3个元素
    A = ['xiaoWang','xiaoZhang','xiaoHua']


    print("-----添加之前，列表A的数据-----")
    for tempName in A:
        print(tempName)


    #提示、并添加元素
    temp = input('请输入要添加的学生姓名:')
    A.append(temp)


    print("-----添加之后，列表A的数据-----")
    for tempName in A:
        print(tempName)

>>> a = [1, 2]
>>> b = [3, 4]
>>> a.append(b)
>>>  print(a) 
[1, 2, [3, 4]]        #运行结果 
>>> a.extend(b)   
>>>  print(a)
[1, 2, [3, 4], 3, 4]   #运行结果

>>> a = [0, 1, 2]
>>> a.insert(1, 3)
>>> print(a)
[0, 3, 1, 2]

# 定义变量A，默认有3个元素
A = ['xiaoWang', 'xiaoZhang', 'xiaoHua']


print("-----修改之前，列表A的数据-----")
for tempName in A:
    print(tempName)


# 修改元素
A[1] = 'Lu'


print("-----修改之后，列表A的数据-----")
for tempName in A:
    print(tempName)

#待查找的列表
nameList = ['xiaoWang','xiaoZhang','xiaoHua']


#获取用户要查找的名字
findName = input('请输入要查找的姓名:')


#查找是否存在
if findName in nameList:
    print('在字典中找到了相同的名字')
else:
    print('没有找到')

>>> a = ['a', 'b', 'c', 'a', 'b']
>>> a.index('a', 1, 3) # 注意是左闭右开区间
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: &#39;a&#39; is not in list
>>> a.index(&#39;a&#39;, 1, 4)
>>>  print(a)
3  #运行结果
>>> a.count(&#39;b&#39;)
>>>  print(a)
2    #运行结果
>>> a.count(&#39;d&#39;)
>>>  print(a)
0    #运行结果

movieName = ['加勒比海盗','骇客帝国','第一滴血','霍比特人','速度与激情']


print('------删除之前------')
for tempName in movieName:
    print(tempName)


del movieName[2]


print('------删除之后------')
for tempName in movieName:
    print(tempName)

movieName = ['加勒比海盗','骇客帝国','第一滴血','霍比特人','速度与激情']


print('------删除之前------')
for tempName in movieName:
    print(tempName)


movieName.pop()


print('------删除之后------')
for tempName in movieName:
    print(tempName)

movieName = ['加勒比海盗','骇客帝国','第一滴血','指环王','霍比特人','速度与激情']


print('------删除之前------')
for tempName in movieName:
    print(tempName)


movieName.remove('指环王')


print('------删除之后------')
for tempName in movieName:
    print(tempName)

>>> a = [1, 4, 2, 3]
>>>  print(a)
[1, 4, 2, 3]    #运行结果
>>> a.reverse()
>>>  print(a)
[3, 2, 4, 1]    #运行结果
>>> a.sort()  
>>>  print(a)
[1, 2, 3, 4]  #运行结果
>>> a.sort(reverse=True)
>>>  print(a)
[4, 3, 2, 1] #运行结果

Names= [['北京','甘肃'],
            ['南京','天津','广东'],
            ['山','上海']]

#encoding=utf-8


import random


# 定义一个列表用来保存3个办公室
offices = [[],[],[]]


# 定义一个列表用来存储8位老师的名字
names = ['A','B','C','D','E','F','G','H']


i = 0
for name in names:
    index = random.randint(0,2)    
    offices[index].append(name)


i = 1
for tempNames in offices:
    print('办公室%d的人数为:%d'%(i,len(tempNames)))
    i+=1
    for name in tempNames:
        print("%s"%name,end='')
    print("\n")
    print("-"*20)