PHP와 MySQL을 사용하여 JSON 배열을 처리하는 방법은 무엇입니까?

CREATE TABLE users (
    id INT PRIMARY KEY AUTO_INCREMENT,
    name VARCHAR(255),
    email VARCHAR(255),
    skills JSON
);

<?php
$conn = new mysqli("localhost", "username", "password", "database");

if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

$data = array(
    "name" => "John Doe",
    "email" => "johndoe@example.com",
    "skills" => json_encode(array("PHP", "MySQL", "JavaScript"))
);

$sql = "INSERT INTO users (name, email, skills) VALUES (?, ?, ?)";
$stmt = $conn->prepare($sql);
$stmt->bind_param("sss", $data['name'], $data['email'], $data['skills']);
$stmt->execute();

$stmt->close();
$conn->close();
?>

<?php
$conn = new mysqli("localhost", "username", "password", "database");

if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

$sql = "SELECT id, name, email, skills FROM users WHERE skills->'$[0]' = 'PHP'";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    while ($row = $result->fetch_assoc()) {
        echo "ID: " . $row["id"] . "<br>";
        echo "Name: " . $row["name"] . "<br>";
        echo "Email: " . $row["email"] . "<br>";
        echo "Skills: " . implode(", ", json_decode($row["skills"])) . "<br>";
        echo "<br>";
    }
} else {
    echo "No results found.";
}

$conn->close();
?>