mysql에서 sql 블록의 사용법은 무엇입니까

SELECT DISTINCT
pg.part_grp_id,
pg.part_grp_name,
pg.equip_category_id
FROM
cost_part_grp pg,
cost_part_kit pk,
cost_part_event pe
WHERE
pe.mdl_ver_id IN (
SELECT
s.mdl_ver_id
FROM
cost_fleet_model s
WHERE
s.fleet_id = 1002
)
AND pe.part_kit_id = pk.part_kit_id
AND pk.part_grp_id = pg.part_grp_id
ORDER BY
CASE pg.equip_category_id
WHEN 2 THEN
1
WHEN 1 THEN
2
WHEN 4 THEN
3
ELSE
4
END

UPDATE t_bss_employees
SET mobilephone = REPLACE (mobilephone, "2129", "0000")
WHERE
id IN (
SELECT
a.id
FROM
(
SELECT
id
FROM
t_bss_employees
WHERE
mobilephone IN (
'18121299262',
'18121299247',
'18121299206',
'18121299209'
)
) AS a
)

select a.style, ROUND(
            b.num / a.sum * 100,
            2
        ) as styleRate from (SELECT 
count(qspc.id) sum 
,qq.style  style
from  t_qc_security_plan_comment  qspc 
inner join t_qc_question qq
on qq.id = qspc.question_id
LEFT JOIN t_qc_address qa ON qa.id = qspc.address_id
LEFT JOIN t_system_organ  so on qa.hospital =  so.id
WHERE qq.scr_level is not NULL
and qq.type = 3  and so.tenant_code = 'zzyy'
GROUP BY style) a left join (SELECT 
count(qspc.id) num 
,qq.style  style
from  t_qc_security_plan_comment  qspc 
inner join t_qc_question qq
on qq.id = qspc.question_id
LEFT JOIN t_qc_address qa ON qa.id = qspc.address_id
LEFT JOIN t_system_organ  so on qa.hospital =  so.id
WHERE qq.scr_level is not NULL
and qq.type = 3  and so.tenant_code = 'zzyy'
and qspc.is_bad =0
GROUP BY style) b on a.style = b.style