파이썬에서 99 구구단을 인쇄하는 방법

i = 1
while(i <=9):
    for j in range (1,i+1): #range()函数左闭右开
        print(&#39;%d*%d=%-3d&#39;%(i,j,i*j),end=&#39;&#39;)
    i += 1
    print()

for i in range(1,10):
    j = 0
    while j < i:
        j += 1
        print("%d*%d=%-3d"%(i,j,i*j),end=&#39;&#39;)
    print( )

a = [1, 2, 3, 4, 5, 6, 7, 8, 9]
for i in a:
    j = 1
    while j <= i:
        print(&#39;%d*%d=%-3d&#39;%(i,j,i*j),end=&#39;\t&#39;)
        # %-3d 是控制输出结果占据3位，且从左面开始对齐
        j += 1
    print( )

print('\n'.join([' '.join(["%2s x%2s = %2s" % (j, i, i*j) for j in range(1, i+1)]) for i in range(1, 10)]))