php mail邮件发送带附件功能

WBOY

풀어 주다： 2016-05-25 16:49:34

원래의

972명이 탐색했습니다.

<html>
 <head>
  <title>带附件的邮件发送</title>
 </head>
 <body> 
  <form method="post" name="form1" action="sendmail.php" ENCTYPE="multipart/form-data"> 
   <table> 
    <tr>
     <td>发送人：</td> 
     <td><input type="text" name="from"></td> 
    </tr> 
    <tr>
     <td>收件人：</td> 
     <td><input type="text" name="to"></td> 
    </tr> 
    <tr>
     <td>邮件主题：</td> 
     <td><input type="text" name="subject"></td> 
    </tr> 
    <tr>
     <td>邮件内容：</td> 
     <td><textarea name="body"></textarea></td> 
    </tr> 
    <tr>
     <td>附件上传：</td> 
     <td><input type="file" name="upload_file"></td> 
    </tr> 
    <tr> 
     <td span=2>
      <input type="submit" value="提交"> 
      <input type="reset" value="重置"> 
     </td> 
    </tr> 
   </table> 
  </form> 
 </body> 
</html>

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sendmail.php文件代码：

<?php 
//获得表单信息
$from = $_POST[&#39;from&#39;];
$to = $_POST[&#39;to&#39;]; 
$subject = $_POST[&#39;subject&#39;]; 
$body = $_POST[&#39;body&#39;]; 
// 定义分界线 
$boundary = "345894369383"; //分界线是一串无规律的字符
//设置header
$header = "Content-type: multipart/mixed; boundary= $boundary/r/n"; 
$header .= "From:$from/r/n"; 
//获得上传文件的文件内容
$file = $_FILES[&#39;upload_file&#39;][&#39;tmp_name&#39;]; 
//确定上传文件的MIME类型 
$mimeType = $_FILES[&#39;upload_file&#39;][&#39;type&#39;]; 
//获得上传文件的文件名 
$fileName = $_FILES[&#39;upload_file&#39;][&#39;name&#39;]; 
//读取上传文件 
$fp = fopen($file, "r"); //打开文件
$read = fread($fp, filesize($file)); //读入文件
$read = base64_encode($read); //base64编码 
$read = chunk_split($read); //切割字符串
//建立邮件的主体，分为邮件内容和附件内容两部分
$body = "--$boundary 
Content-type: text/plain; charset=iso-8859-1 
Content-transfer-encoding: 8bit 
$body 
--$boundary 
Content-type: $mimeType; name=$fileName 
Content-disposition: attachment; filename=$fileName 
Content-transfer-encoding: base64 
$read 
--$boundary--"; 
//发送邮件 并输出是否发送成功的信息
if(mail($to, $subject,$body,$header)) 
{
echo "信件发送成功"; 
}
else 
{
echo "信件发送失败"; 
}
?>

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