Ajax는 json 데이터를 반환하기 위해 return php 인터페이스를 호출하는 방법을 구현합니다.

<?php

  header(&#39;Content-Type: application/json&#39;);
  header(&#39;Content-Type: text/html;charset=utf-8&#39;);

  $email = $_GET[&#39;email&#39;];

  $user = [];

  $conn = @mysql_connect("localhost","Test","123456") or die("Failed in connecting database");
  mysql_select_db("Test",$conn);
  mysql_query("set names &#39;UTF-8&#39;");
  $query = "select * from UserInformation where email = &#39;".$email."&#39;";
  $result = mysql_query($query);
  if (null == ($row = mysql_fetch_array($result))) {
    echo $_GET[&#39;callback&#39;]."(no such user)";
  } else {
    $user[&#39;email&#39;] = $email;
    $user[&#39;nickname&#39;] = $row[&#39;nickname&#39;];
    $user[&#39;portrait&#39;] = $row[&#39;portrait&#39;];
    echo $_GET[&#39;callback&#39;]."(".json_encode($user).")";
  }

?>

<script>
    $.ajax({
      url: "http://test.localhost/UserInterfaceForChatroom/UserInformation.php?email=pshuyue@gmail.com",
      type: "GET",
      dataType: &#39;jsonp&#39;,
      //      crossDomain: true,
      success: function (result) {
        //        data = $.parseJSON(result);
        //        alert(data.nickname);
        alert(result.nickname);
      }
    });
  </script>

$ret['foo'] = "bar";
finish();

function finish() {
  header("content-type:application/json");
  if ($_GET['callback']) {
    print $_GET['callback']."(";
  }
  print json_encode($GLOBALS['ret']);
  if ($_GET['callback']) {
    print ")";
  }
  exit; 
}