문자열에 하위 문자열이 나타나는 횟수를 계산하는 PHP 함수 substr_count()

<?php
echo substr_count("Hello world. The world is nice","world");
?>

substr_count(string,substring,start,length)

<?php
$str = "This is nice";
echo strlen($str)."<br>"; // Using strlen() to return the string length
echo substr_count($str,"is")."<br>"; // The number of times "is" occurs in the string
echo substr_count($str,"is",2)."<br>"; // The string is now reduced to "is is PHP"
echo substr_count($str,"is",3)."<br>"; // The string is now reduced to "s is PHP"
echo substr_count($str,"is",3,3)."<br>"; // The string is now reduced to "s i"
?>

<?php
$str = "abcabcab"; 
echo substr_count($str,"abcab"); // This function does not count overlapped substrings
?>

<?php
echo $str = "This is nice";
substr_count($str,"is",3,9);
?>

<?php
$text = &#39;This is a test&#39;;
echo strlen($text) . &#39;<br />&#39;; // 输出14
 
echo substr_count($text, &#39;is&#39;) . &#39;<br />&#39;; // 2
 
// the string is reduced to &#39;s is a test&#39;, so it prints 1
echo substr_count($text, &#39;is&#39;, 3) . &#39;<br />&#39;;//实际上就是从第四个字符开始查找是否在$text中含有is
 
// the text is reduced to &#39;re &#39;, so it prints 0
echo substr_count($text, &#39;are&#39;, 16, 3) . &#39;<br />&#39;;
 
// the text is reduced to &#39;s i&#39;, so it prints 0echo substr_count($text, &#39;is&#39;, 3, 3);
 
// generates a warning because 5+10 > 14
echo substr_count($text, &#39;is&#39;, 5, 10) . &#39;<br />&#39;;
 
 
// prints only 1, because it doesn&#39;t count overlapped subtrings
$text2 = &#39;gcdgcdgcd&#39;;
echo substr_count($text2, &#39;gcdgcd&#39;) . &#39;<br />&#39;;
 ?>