이미지 내용을 읽고 브라우저에 출력하기 위한 PHP용 코드 공유

<?php
//输出图片内容到浏览器
//by bbs.it-home.org
class imgdata{
 public $imgsrc;
 public $imgdata;
 public $imgform;
 public function getdir($source){
  $this->imgsrc  = $source;
 }
 public function img2data(){
  $this->_imgfrom($this->imgsrc);
  return $this->imgdata=fread(fopen($this->imgsrc,'rb'),filesize($this->imgsrc));
 }
 public function data2img(){
  header("content-type:$this->imgform");
  echo $this->imgdata;
  //echo $this->imgform;
  //imagecreatefromstring($this->imgdata);
 }
 public function _imgfrom($imgsrc){
  $info=getimagesize($imgsrc);
  //var_dump($info);
  return $this->imgform = $info['mime'];
 }
}
$n = new imgdata;
$n -> getdir("1.jpg");
$n -> img2data();
$n -> data2img();
?>

<?php
$size = getimagesize($filename); //获取mime信息
$fp=fopen($filename, "rb"); //二进制方式打开文件
if ($size && $fp) {
header("Content-type: {$size['mime']}");
fpassthru($fp); // 输出至浏览器
exit;
} else {
// error
}
?>