PHP怎样实现单击“添加”按钮增加一行表单项，并将所有内容插入到数据库中

<meta http-equiv="content-type" content="text/html;charset=utf-8"><script language="javascript" type="text/javascript" src="jquery.min.js"></script><script type="text/javascript">$(function(){    $(':button[name=add]').click(function(){        insertTr();    })    $('button[name=del]').click(function(){        $(this).parents('tr').remove();    })    $(':button[name=delall]').click(function(){        $('.itme').remove();    })})var gradeI=1;function insertTr(){    var html='';    html+='<tr class="itme"><td><input type="text" name="data[time][]">';    html+='<td><input type="radio" name="data[grade]['+gradeI+']" value="1">好<input type="radio" name="data[grade]['+gradeI+']" value="2">很好';    html+='<td><select name="data[type][]"><option value="优秀生">优秀生<option value="三好生">三好生';    html+='<td><button name="del">删除';    $('#tab').append(html);    $('button[name=del]').click(function(){        $(this).parents('tr').remove();    })       gradeI++;}</script> 

<?php $arr_time=$_POST['data']['time'];$arr_grade=$_POST['data']['grade'];$arr_type=$_POST['data']['type']; for($i=0;$i<count($arr_time);$i++){    $insert[$i]['time']=$arr_time[$i];    $insert[$i]['grade']=$arr_grade[$i];    $insert[$i]['type']=$arr_type[$i];} echo "<pre class="brush:php;toolbar:false">";print_r($insert);echo "