如何根据ID获取同一行中的某一个字段
现在有字段 ID , BODY；
我现在根据ID=100获取了同一行的BODY,echo出body，
然后现在还要需要根据id+1 也就是 获取 ID=101 行的body 一样 echo出来。
获取下一个id的 body 这个要怎么写？
<br />
$sql = "SELECT * FROM `shops` WHERE `id` > '100' limit 1 order by id asc";<br />
$s = $db->getLine($sql);<br />
$shop = array(<br />
'body' => $s['body'],<br />
);<br />
<br />
$sql = "SELECT * FROM `shops` WHERE `id` = '101'";<br />
$s = $db->getLine($sql);<br />
$shop = array(<br />
'body' => $s['body'],<br />
);<br />
$sql = "SELECT * FROM `shops` WHERE `id` > '100' limit 1 order by id ASC limit 1";<br />
$s = $db->getLine($sql);<br />
$shop = array(<br />
'body' => $s['body'],<br />
);<br />
![[웹 프런트엔드] Node.js 빠른 시작](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
