如何把数组的值变成健名形成新的数组。
本帖最后由 xuexi123abc163 于 2014-11-24 11:40:57 编辑
(
[0] => Array
(
[ak] => 1
[fs] => 12
[tss] => sd第三方f
)
[1] => Array
(
[ak] => 2
[fs] => 12
[tss] => 是的发生
)
[2] => Array
(
[ak] => 3
[fs] => 22
[tss] => 好新玩
)
[3] => Array
(
[ak] => 4
[fs] => 22
[tss] => 八实得分
)
[4] => Array
(
[ak] => 6
[fs] => 22
[tss] => 八实得分
)
)
上面的数组是$abc
我下奶想形成新的数组把fs的值作为键名,然后把fs的值相同的,形成新的数组,。。
数组如下:
(
[12] => Array
(
[0] => Array
(
[ak] => 2
[tss] => 是的发生
)
[1] => Array
(
[ak] => 2
[tss] => 是的发生
)
)
[22] => Array
(
...............
)
)
------解决思路----------------------$ar = array (<br /> array (<br /> 'ak' => '1',<br /> 'fs' => '12',<br /> 'tss' => 'sd第三方f',<br /> ),<br /> array (<br /> 'ak' => '2',<br /> 'fs' => '12',<br /> 'tss' => '是的发生',<br /> ),<br /> array (<br /> 'ak' => '3',<br /> 'fs' => '22',<br /> 'tss' => '好新玩',<br /> ),<br /> array (<br /> 'ak' => '4',<br /> 'fs' => '22',<br /> 'tss' => '八实得分',<br /> ),<br /> array (<br /> 'ak' => '6',<br /> 'fs' => '22',<br /> 'tss' => '八实得分',<br /> ),<br />);<br />$res = array();<br />foreach($ar as $r) {<br /> $t = $r['fs'];<br /> unset($r['fs']);<br /> $res[$t][] = $r;<br />}<br />print_r($res);
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Array<br />(<br /> [12] => Array<br /> (<br /> [0] => Array<br /> (<br /> [ak] => 1<br /> [tss] => sd第三方f<br /> )<br /><br /> [1] => Array<br /> (<br /> [ak] => 2<br /> [tss] => 是的发生<br /> )<br /><br /> )<br /><br /> [22] => Array<br /> (<br /> [0] => Array<br /> (<br /> [ak] => 3<br /> [tss] => 好新玩<br /> )<br /><br /> [1] => Array<br /> (<br /> [ak] => 4<br /> [tss] => 八实得分<br /> )<br /><br /> [2] => Array<br /> (<br /> [ak] => 6<br /> [tss] => 八实得分<br /> )<br /><br /> )<br /><br />)<br /><br />
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