DOM 처리 후 XML에서 속성 순서를 어떻게 보존할 수 있습니까?

import javax.xml.parsers.SAXParserFactory;
import javax.xml.parsers.SAXParser;
import org.xml.sax.SAXException;
import org.xml.sax.InputSource;
import org.xml.sax.SAXNotRecognizedException;
import org.xml.sax.SAXNotSupportedException;
import org.xml.sax.XMLReader;
import org.xml.sax.ContentHandler;
import org.xml.sax.helpers.DefaultHandler;

public class PreserveAttributeOrderSAX {

    public static void main(String[] args) throws SAXException {
        SAXParserFactory spf = SAXParserFactoryImpl.newInstance();
        spf.setNamespaceAware(true);
        spf.setValidating(false);
        try {
            spf.setFeature("http://xml.org/sax/features/validation", false);
            spf.setFeature("http://apache.org/xml/features/nonvalidating/load-dtd-grammar", false);
            spf.setFeature("http://apache.org/xml/features/nonvalidating/load-external-dtd", false);
            SAXParser sp = spf.newSAXParser();
            XMLReader reader = sp.getXMLReader();
            ContentHandler handler = new AttributeOrderContentHandler();
            reader.setContentHandler(handler);
            reader.parse(new InputSource("sample.xml"));
        } catch (SAXNotSupportedException | SAXNotRecognizedException e) {
            e.printStackTrace();
        }
    }
}

private static class AttributeOrderContentHandler extends DefaultHandler {

    @Override
    public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException {
        for (int i = 0; i < attributes.getLength(); i++) {
            String name = attributes.getQName(i);
            String value = attributes.getValue(i);
            // Process the attribute with its preserved order
        }
    }
}