정확한 두 자리 돈 계산에 대해 PHP의 '정밀도' 해결 방법을 신뢰할 수 있습니까?

ini_set('precision', 8);
$a = 5.88; // cost of 1kg
$q = 2.49; // User buys 2.49 kg
$b = $a * 0.01; // 10% Discount only on first kg
echo ($a * $q) - $b; // result: 14.5824 (not precise for money calculations)

$a = 342349.23;
$b = 341765.07;

ini_set('precision', 20);
echo $a - $b, PHP_EOL; // 584.15999999997438863
echo floatval(round($a - $b, 2)), PHP_EOL; // 584.15999999999996817 (rounding issue)
echo number_format($a - $b, 2), PHP_EOL; // 584.16
echo bcsub($a, $b, 2), PHP_EOL; // 584.15 (precision set to 20)

ini_set('precision', 14);
echo $a - $b, PHP_EOL; // 584.15999999997
echo floatval(round($a - $b, 2)), PHP_EOL; // 584.16
echo number_format($a - $b, 2), PHP_EOL; // 584.16
echo bcsub($a, $b, 2), PHP_EOL; // 584.16 (precision set to 14)

ini_set('precision', 6);
echo $a - $b, PHP_EOL; // 584.16
echo floatval(round($a - $b, 2)), PHP_EOL; // 584.16
echo number_format($a - $b, 2), PHP_EOL; // 584.16
echo bcsub($a, $b, 2), PHP_EOL; // 584.00 (precision set to 6)

ini_set('precision', 3);
echo $a - $b, PHP_EOL; // 584
echo floatval(round($a - $b, 2)), PHP_EOL; // 584
echo number_format($a - $b, 2), PHP_EOL; // 584.16
echo bcsub($a, $b, 2), PHP_EOL; // 0.00 (precision set to 3)

$a = 0.19;
$b = 0.16;
...
$h = $a + $b + ...; // Total value: 0.4

$i = $h - $a - $b - ...; // Result: 1.0408341E-17 (expected: 0.00)