Go에서 WaitGroups 및 버퍼링된 채널을 사용할 때 교착 상태를 방지하려면 어떻게 해야 합니까?

<code class="go">package main

import "fmt"
import "sync"

func main() {
    ch := make(chan []int, 4)
    var m []int

    var wg sync.WaitGroup
    for i := 0; i < 5; i++ {
        wg.Add(1)
        go func() {
            defer wg.Done()
            ch <- m // Sending to a full channel
            return
        }()
    }
    wg.Wait()

    for c := range ch {
        fmt.Printf("c is %v", c)
    }
}</code>

<code class="go">ch := make(chan []int, 5)
...
wg.Wait()
close(ch)</code>

<code class="go">func main() {
    ch := make(chan []int, 4)
    var m []int

    var wg sync.WaitGroup
    for i := 0; i < 5; i++ {
        wg.Add(1)
        go func() {
            ch <- m
            wg.Done()
        }()
    }
    go func() {
        for c := range ch {
            fmt.Printf("c is %v\n", c)
            wg.Done()
        }
    }()
    wg.Wait()
}</code>