FastAPI에서 오류 응답을 사용자 정의하는 방법은 무엇입니까?

<code class="python">from fastapi import FastAPI, Body, Request, status
from fastapi.encoders import jsonable_encoder
from fastapi.exceptions import RequestValidationError
from fastapi.responses import JSONResponse

app = FastAPI()

@app.exception_handler(RequestValidationError)
async def validation_exception_handler(request: Request, exc: RequestValidationError):
    return JSONResponse(
        status_code=status.HTTP_422_UNPROCESSABLE_ENTITY,
        content=jsonable_encoder({
            "detail": exc.errors(),  # optionally include the errors
            "body": exc.body,
            "custom msg": {"Your error message"}
        }),
    )

class Demo(BaseModel):
    content: str = None

@app.post("/demo")
async def demo_func(d: Demo):
    return d.content</code>

<code class="python">from fastapi.responses import PlainTextResponse

@app.exception_handler(RequestValidationError)
async def validation_exception_handler(request, exc):
    return PlainTextResponse(str(exc), status_code=422) </code>