FastAPI에서 잘못된 요청에 대한 오류 응답을 사용자 정의하는 방법은 무엇입니까?

from fastapi import FastAPI

app = FastAPI

class Demo(BaseModel):
    content: str = None

@app.post("/demo")
async def demoFunc(d: Demo):
    return d.content

{
  "detail": [
    {
      "loc": [
        "body",
        47
      ],
      "msg": "Extra data: line 4 column 2 (char 47)",
      "type": "value_error.jsondecode",
      "ctx": {
        "msg": "Extra data",
        "doc": "{\n  \"content\": \"some text here\"}aaaaa",
        "pos": 47,
        "lineno": 4,
        "colno": 2
      }
    }
  ]
}

from fastapi import FastAPI, Body, Request, status
from fastapi.encoders import jsonable_encoder
from fastapi.exceptions import RequestValidationError
from fastapi.responses import JSONResponse

app = FastAPI()

@app.exception_handler(RequestValidationError)
async def validation_exception_handler(request: Request, exc: RequestValidationError):
    return JSONResponse(
        status_code=status.HTTP_422_UNPROCESSABLE_ENTITY,
        content=jsonable_encoder({
            "detail": exc.errors(),
            "body": exc.body,
            "custom msg": {
                "Your error message"
            }
        }),
    )

{
    "detail": [
        {
            "loc": ["body", 1],
            "msg": "invalid json",
            "type": "json.decoder.JSONDecodeError",
            "ctx": {}
        }
    ],
    "body": {},
    "custom msg": {
        "Your error message"
    }
}

from fastapi.responses import PlainTextResponse

@app.exception_handler(RequestValidationError)
async def validation_exception_handler(request, exc):
    return PlainTextResponse(str(exc), status_code=422)