用jquery生成二级菜单的实例代码_jquery-JS 튜토리얼-php.cn

用jquery生成二级菜单的实例代码_jquery

WBOY

풀어 주다： 2016-05-16 17:31:36

원래의

1011명이 탐색했습니다.

javascript

页面中的函数

复制代码代码如下:

function querySub(id,sid/*选中的项*/){
$.post('${path}/page/article/querySubChannelArticle.action', 
                {'channelId':id},function(data){ 
                    $('select[name="article.subChannel.subId"] option[value!=""]').remove(); 
                    var jsonObj = data;    
                    for ( var i = 0; i                         var $option = $(''); 
                        $option.attr('value',jsonObj[i].subId); 
                        if(jsonObj[i].subId === sid){ 
                            $option.attr('selected',true); 
                        } 
                        $option.text(jsonObj[i].subName); 
                        $('select[name="article.subChannel.subId"]').append($option); 
                    } 
                }); 
        } 

        $(function(){ 
            querySub(,); 
        }); 
 

页面代码：

复制代码代码如下:

                    一级栏目





                    二级栏目

服务器端

复制代码代码如下:

 public String querySubChannelArticle(){  
        HttpServletResponse response=getResponse(); 
        HttpServletRequest request=getRequest(); 
        response.setContentType("application/json; charset=UTF-8"); 
        PrintWriter out =null; 
        try { 
            out = response.getWriter(); 

            List> list = new LinkedList>(); 
            if(channelId!=null && !channelId.equals("")){ 
                Channel tmp = new Channel(); 
                tmp.setChannelId(Integer.parseInt(channelId)); 
                subChannelList = subChannelDAO.listSubChannel(tmp); 

                for(Object oo:subChannelList){ 
                    Map obj = new HashMap(); 
                    SubChannel c = (SubChannel)oo; 
                    obj.put("subId", c.getSubId()); 
                    obj.put("subName", c.getSubName()); 
                    list.add(obj); 
                } 
            } 
            String outStr = JsonUtil.toJSONStr(list); 
            out.println(outStr); 
        }catch(Exception e){ 
        e.printStackTrace(); 
        } 
        out.flush(); 
        out.close(); 
        return null; 
    }   

其实蛮简洁的