有人说用归并算法，但是执行下来时间远远不止2s。
在下实在想不出还有什么好办法，希望各位能给个提示或者解法，谢谢。

下面是我的测试代码：

  public class TestA {

    public static void main(String[] args) {
        long[] a = new long[50000000];
        long num = 13000000000l;
        for (int i = 0; i < a.length; i++) {
            a[i] = (num + i);
        }
        long[] b = new long[10000000];
        long num2 = 14000000000l;
        for (int i = 0; i < b.length - 2; i++) {
            b[i] = (num2 + i);
        }
        b[9999999] =  13000000000l;
        b[9999998] =  13000000001l;

        long[] c = new long[a.length+b.length];
        long start = System.currentTimeMillis();
        for (int i = 0; i < a.length; i++) {
            c[i] = a[i];
        }
        for (int i = 0; i < b.length; i++) {
            c[i + a.length] = b[i];
        }
        System.out.println("start");
        sort(c, 0, c.length-1);
        long end = System.nanoTime();
        System.out.println(System.currentTimeMillis() - start);
        for (int i = 0; i < c.length; i++) {
            
            System.out.println(c[i]);
        }

    }

    public static void sort(long[] data, int left, int right) {
        if (left < right) {
            // 找出中间索引
            int center = (left + right) / 2;
            // 对左边数组进行递归
            sort(data, left, center);
            // 对右边数组进行递归
            sort(data, center + 1, right);
            // 合并
            merge(data, left, center, right);
        }
    }

    public static void merge(long[] data, int left, int center, int right) {
        long[] tmpArr = new long[data.length];
        int mid = center + 1;
        // third记录中间数组的索引
        int third = left;
        int tmp = left;
        while (left <= center && mid <= right) {

            // 从两个数组中取出最小的放入中间数组
            if (data[left] <= data[mid]) {
                if(data[left] == data[mid]){
                    System.out.println(data[left]);
                }
                tmpArr[third++] = data[left++];
             
            } else {
                tmpArr[third++] = data[mid++];
            }
        }
        // 剩余部分依次放入中间数组
        while (mid <= right) {
            tmpArr[third++] = data[mid++];
        }
        while (left <= center) {
            tmpArr[third++] = data[left++];
        }
        // 将中间数组中的内容复制回原数组
        while (tmp <= right) {
            data[tmp] = tmpArr[tmp++];
        }
    }

}