2016/12/8
根据我的了解, find中一般使用shell通配符, 但是shell通配符的表达能力不是很强, 所以就想使用正则, 但是结果不如人意.
查阅了文档, 自认为是按照文档的描述做的, 不知问题出在何处.
定制的find命令
find-regex() { # find-regex $path $pattern if [ $# = 0 ]; then echo "Usage: find-regex $path $pattern" else find "$1" -regextype posix-egrep -regex "$2" fi }
man find
-regextype type Changes the regular expression syntax understood by -regex and -iregex tests which occur later on the command line. Currently-implemented types are emacs (this is the default), posix-awk, posix-basic, posix-egrep and posix-extended.
用法是没有问题的,之所以没有得到你想要的结果可能是因为
"$2"
双引号包含的$2内的特殊字符有可能会被shell所解释。